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Split 4044x(6x4)(4x+8) into partial fractions.

Input the partial fractions here: Expected answer: .

 

 

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Advice

We use partial fractions to find A and B such that: 
44x+40(6x4)(4x+8)=A6x4+B4x+8

Multiplying both sides of the equation by 1(6x4)(4x+8) we obtain:

A(4x+8)+B(6x4)=44x+40(4A+6B)x+8A4B=44x+40

Identifying coefficients:

Constant term: 8A4B=40

Coefficent x: 4A+6B=44 

On solving these equations we obtain A=1 and B=8

Which gives:44x+40(6x4)(4x+8)=16x484x+8