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\\[\\simplify{{b}x+{c}=y}\\]

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$x=$ [[0]]

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\\[\\simplify{ (x+{a})^2-{b}=y+{c} }\\]

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$x=$ [[0]]

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\\[\\simplify{ 1/({a}x)+{b}=y }\\] 

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\\[ \\simplify{y=(e^({c}x))/{b}-{a}} \\]

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$x=$ [[0]]

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Rearrange the following equations to make $x$ the subject.

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Rearrange equations to make $x$ the subject.

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