// Numbas version: exam_results_page_options {"name": "Kuis Persamaan Diferensial Orde Dua", "metadata": {"description": "", "licence": "None specified"}, "duration": 3000, "percentPass": "75", "showQuestionGroupNames": true, "showstudentname": true, "question_groups": [{"name": "Kuis PD Orde 2", "pickingStrategy": "all-ordered", "pickQuestions": 1, "questions": [{"name": "Pers. Diferensial Homogen", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Arini Soesatyo Putri", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4647/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "

Solusi dari persamaan diferensial homogen $y^{\"}+y^{'}-20y=0$ adalah?

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Dalam menentukan solusi partikular dari persamaan diferensial

\n

$y^{\"}+6y^{'}+9y=2e^{-3x}$

\n

dengan menggunakan koefisien taktentu, maka pemisalan yang digunakan adalah?

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Solusi partikular dari persamaan diferensial

\n

$y^{\"}-2y^{'}+10y=13sin(3x)-4cos(3x)$

\n

adalah?

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Solusi dari persamaan diferensial

\n

$y^{\"}+4y=8sec^{3}(2x)$

\n

dengan $y(0)=2$ dan $y'(0)=4$

\n

adalah

\n

Ket:

\n

tulis ekspresi fungsinya saja (dalam x)

\n

perkalian gunakan * (contoh x*sin(x))

\n

pangkat dan sinus gunakan tanda kurung (contoh e^(-x), sin(x))

\n

invers trigonometri gunakan arcsin(x), arccos(x), arctan(x)

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$y=cos(2x)+2sin(2x)+\\frac{1}{cos(2x)}

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Diberikan persamaan diferensial homogen

\n

$4y^{\"}+4y^{'}+1=0$

\n

dengan $y(0)=2$ dan $y(1)=e^{-1/2}$.

", "advice": "

a) $y=2e^(-1/2x)-xe^(-1/2x)$

\n

b) 2

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Cari solusi $y(x)$

\n

tulis ekspresi fungsinya saja

\n

perkalian gunakan * (contoh x*sin(x))

\n

pangkat dan trigonometri gunakan tanda kurung (contoh e^(-x), sin(x))

\n

invers trigonometri gunakan arcsin(x), arccos(x), arctan(x)

\n

$y = $

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Nilai dari $\\lim\\limits_{x \\rightarrow \\infty} y(x)$ adalah...

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Diberikan persamaan diferensial

\n

$y^{\"}+2y^{'}+1=\\frac{e^{-x}}{1+x^2}$

\n

(a) Salah satu dari dua solusi yang saling bebas adalah $u_1 = e^{-x}$. Yang lainnya adalah $u_2 = ...$

\n

(b) Misalkan $y_{p}=v_{1}(x)u_{1}(x)+v_{2}(x)u_{2}(x)$. Maka $v_{1}(x)$ dan $v_{2}(x)$ adalah

\n

Ket:

\n

Jawaban langsung ekspresi fungsinya

\n

Jawablah secara berturut-turut diisi pada kotak di bawah ini:

\n

perkalian gunakan * (contoh x*sin(x))

\n

pangkat dan trigonometri gunakan tanda kurung (contoh e^(-x), sin(x))

\n

invers trigonometri gunakan arcsin(x), arccos(x), arctan(x)

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$u_{1} = $

\n

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$v_1$ =

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$v_2$ =

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Waktu sudah habis!

"}, "timedwarning": {"action": "warn", "message": "

Waktu tinggal 5 menit lagi, semangat!

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Kuis Bab Persamaan Diferensial Orde Dua. Selamat Mengerjakan. Good Luck!

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