// Numbas version: exam_results_page_options {"name": "Weitere \u00dcbungen (Lektion 3)", "metadata": {"description": "

Übungen zu Stellenwertsysteme, Euklidischer Algorithmus

", "licence": "Creative Commons Attribution-NonCommercial-NoDerivs 4.0 International"}, "duration": 0, "percentPass": 0, "showQuestionGroupNames": false, "showstudentname": true, "question_groups": [{"name": "Group", "pickingStrategy": "all-ordered", "pickQuestions": 1, "questionNames": ["", "", ""], "questions": [{"name": "Stellenwertdarstellungen", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Andreas Vohns", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3622/"}], "tags": [], "metadata": {"description": "

Zifferndarstellungen in b-adischen Systemen

", "licence": "Creative Commons Attribution-NonCommercial-NoDerivs 4.0 International"}, "statement": "

Die folgenden Beispiele ergeben jeweils eine vierstellige Zahl in einem Stellenwertsystem zur Basis $b$, die einzelnen Stellenwerte sind jeweils durch Beistrich (,) getrennt.

", "advice": "

Aufgrund des binomischen Lehrsatzes ergibt sich stets dieselbe Zifferndarstellung:

\n

a) $\\var{number1}=\\left(\\var{bases[0]}+1\\right)^3=\\left(\\var{bases[0]}^3+3\\cdot\\var{bases[0]}^2+3\\cdot\\var{bases[0]}^1+1\\cdot\\var{bases[0]}^0\\right)=\\left(1,3,3,1\\right)_\\var{bases[0]}$

\n

b) $\\var{number2}=\\left(\\var{bases[1]}+1\\right)^3=\\left(\\var{bases[1]}^3+3\\cdot\\var{bases[1]}^2+3\\cdot\\var{bases[1]}^1+1\\cdot\\var{bases[1]}^0\\right)=\\left(1,3,3,1\\right)_\\var{bases[1]}$

\n

c) $\\var{number3}=\\left(\\var{bases[2]}+1\\right)^3=\\left(\\var{bases[2]}^3+3\\cdot\\var{bases[2]}^2+3\\cdot\\var{bases[2]}^1+1\\cdot\\var{bases[2]}^0\\right)=\\left(1,3,3,1\\right)_\\var{bases[2]}$

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Stellen Sie die Dezimalzahl $\\var{number1}$ im Stellenwertsystem zur Basis $\\var{bases[0]}$ dar. 

\n

Lösung: $\\Bigg($[[0]]$,$[[1]]$,$[[2]]$,$[[3]]$\\Bigg)_\\var{bases[0]}$

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Stellen Sie die Dezimalzahl $\\var{number2}$ im Stellenwertsystem zur Basis $\\var{bases[1]}$ dar. 

\n

Lösung: $\\Bigg($[[0]]$,$[[1]]$,$[[2]]$,$[[3]]$\\Bigg)_\\var{bases[1]}$

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Stellen Sie die Dezimalzahl $\\var{number3}$ im Stellenwertsystem zur Basis $\\var{bases[2]}$ dar. 

\n

Lösung: $\\Bigg($[[0]]$,$[[1]]$,$[[2]]$,$[[3]]$\\Bigg)_\\var{bases[2]}$

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d)

\n

Was stellen Sie beim Vergleich der Ergebnisse fest? Woran liegt das?

\n

Nur zum Überlegen, wird nicht bewertet!

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Aufgabe zum schriftlichen Addieren in b-adischen Systemen

", "licence": "Creative Commons Attribution-NonCommercial-NoDerivs 4.0 International"}, "statement": "

Wir wollen die Summe der Zahlen $\\left(\\var{z14},\\var{z13},\\var{z12},\\var{z11}\\right)_\\var{base}$ und $\\left(\\var{z24},\\var{z23},\\var{z22},\\var{z21}\\right)_\\var{base}$ ermitteln.

", "advice": "

a)

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\Big(${z14},{z13},{z12},{z11}$\\Big)_\\var{base}$
$+\\Big(${z24 },{z23},{z22},{z21}$\\Big)_\\var{base}$
{u3}{u2}{u1}
$\\Big(${e4},{e3},{e2},{e1}$\\Big)_\\var{base}$
\n

b)

\n

$\\left(\\var{z14},\\var{z13},\\var{z12},\\var{z11}\\right)_\\var{base}=\\var{z14}\\cdot\\var{base}^3+\\var{z13}\\cdot\\var{base}^2+\\var{z12}\\cdot\\var{base}^1+\\var{z11}\\cdot\\var{base}^0=\\var{a}$

\n

$\\left(\\var{z24},\\var{z23},\\var{z22},\\var{z21}\\right)_\\var{base}=\\var{z24}\\cdot\\var{base}^3+\\var{z23}\\cdot\\var{base}^2+\\var{z22}\\cdot\\var{base}^1+\\var{z21}\\cdot\\var{base}^0=\\var{b}$

\n

$\\var{a}+\\var{b}=\\var{sum}=\\var{e4}\\cdot\\var{base}^3+\\var{e3}\\cdot\\var{base}^2+\\var{e2}\\cdot\\var{base}^1+\\var{e1}\\cdot\\var{base}^0$

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Ermitteln Sie die Summe schriftliche ohne vorherige Umwandlung in das Dezimalsystem!

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\Big(${z14},{z13},{z12},{z11}$\\Big)_\\var{base}$
$+\\Big(${z24},{z23},{z22},{z21}$\\Big)_\\var{base}$
[[4]][[5]][[6]]
$\\Big($[[0]],[[1]],[[2]],[[3]]$\\Big)_\\var{base}$
\n

Hinweis: Tragen Sie führ fehlende Überträge bitte eine $0$ ein!

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Wandeln Sie die beiden Zahlen und deren Summe in das Dezimalsystem um!

\n

$\\left(\\var{z14},\\var{z13},\\var{z12},\\var{z11}\\right)_\\var{base}=$[[0]]

\n

$\\left(\\var{z24},\\var{z23},\\var{z22},\\var{z21}\\right)_\\var{base}=$[[1]]

\n

$\\left(\\var{z14},\\var{z13},\\var{z12},\\var{z11}\\right)_\\var{base}+\\left(\\var{z24},\\var{z23},\\var{z22},\\var{z21}\\right)_\\var{base}=$[[2]] 

\n

 

\n

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Aufgabe zum einfachen und erweiterten euklidischen Algorithmus (mit \"schönen\" Zahlen)

", "licence": "Creative Commons Attribution-NonCommercial-NoDerivs 4.0 International"}, "statement": "

 In dieser Aufgabe geht es um den einfachen und den erweiterten Euklidischen Algorithmus.

", "advice": "

a) $\\operatorname{ggT}(\\var{a},\\var{b})=\\var{ergebnis[0]}$

\n
Rechenweg:
{app}
\n
 
\n
b) Durch Rückeinsetzung in die Zeilen oben ermittelt man $r=\\var{ergebnis[1]},s=\\var{ergebnis[2]}$
\n

Eine ausführliche Rechenanleitung finden Sie zB hier.
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Ermitteln Sie mittels Euklidischem Algorithmus: $\\operatorname{ggT}(\\var{a},\\var{b})=$[[0]]

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Ermitteln Sie mittels erweitertem Euklidischem Algorithmus Zahlen $r,s\\in\\mathbb{Z}$, für die gilt:

\n

$r\\cdot \\var{a}+s\\cdot \\var{b}=\\operatorname{ggT}(\\var{a},\\var{b})$

\n

$r=$[[0]] , $s=$[[1]]

\n

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