// Numbas version: exam_results_page_options {"name": "\u00dcbungen (Lektion 6)", "metadata": {"description": "

Griechisch-römische Antike 3

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Über den Weg des Lichts

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

Wählen Sie die korrekte Aussage aus!

", "advice": "

Heron nennt als Gesetz das Nehmen des kürzesten Wegs, dies entspricht innerhalkb desselben Mediums zwar dem schnellsten Weg, aber nicht mehr, wenn verschiedene Medien (z.B. Wasser und Luft) durchdrungen werden.

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Einfallswinkel = Ausfallswinkel ist nicht das Gesetz, sondern eine Folgerung aus dem Gesetz, ebenso die geradlinige Ausbreitung.

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Heron nennt in seiner Katroptik das Gesetz:

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Lösen einer quadratischen Gleichung im Stile Diophants

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Wir betrachten ein weiteres Problem der Form: Zwei Zahlen finden, deren Summe und deren Summe der Quadrate der Zahlen gegeben sind.

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Summe sei $\\var{sum}$, Quadratsumme $\\var{qsum}$.

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Wir bezeichnen die Differenz der beiden Zahlen mit $2\\cdot x$.

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", "advice": "

a) Es ist $a=\\frac{\\var{sum}}{2}-x=\\var{sum/2}-x$, $b=\\frac{\\var{sum}}{2}+x=\\var{sum/2}+x$.

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b) Es ergibt sich: $\\var{qsum}=2\\cdot\\var{(sum/2)^2}+2x^2\\Leftrightarrow x^2=\\frac{\\var{qsum}-\\var{2*(sum/2)^2}}{2}=\\frac{\\var{(qsum-2*(sum/2)^2)}}{2}=\\var{(qsum-2*(sum/2)^2)/2}\\Leftrightarrow x=\\var{x}$

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Dann ist die kleinere der beiden Zahlen $a=$[[0]] und die größere der beiden Zahlen $b=$[[1]].

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Jeweils einen Term in Abhängigkeit von $x$ eintragen!

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Durch Einsetzen dieser Terme in $\\var{qsum}=a^2+b^2$ ermittelt man daraus:

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$x=$[[2]] , $a=$[[0]] , $b=$[[1]]

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Nach Nikomachos: Ermitteln der 5. Proportion

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Nach Nikomachos stehen drei Zahlen $a<b<c$ dann in der \"fünften Proportion\", wenn die mittlere Zahl sich zur kleinere Zahl verhält, wie sich deren Differenz zur Differenz der größeren Zahl und der mittleren Zahl verhält.

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", "advice": "

a) Es gilt: $b:a=(b-a):(c-a)$

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b) Durch probieren (oder auflösen der Gleichung oben) kann man mehrere Lösungen finden, eine mögliche Lösung ist $2, 4, 5$, sowie alle ganzzahligen Vielfachen dieser Lösung.

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Beschreiben Sie die Proportion durch eine Gleichung in den Variablen $a,b,c$:

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$\\Big($[[0]]$\\Big):\\Big($[[1]]$\\Big)=\\Big($[[2]]$\\Big):\\Big($[[3]]$\\Big)$

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Finden Sie drei natürliche Zahlen $a<b<c$, die in fünfter Proportion stehen:

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{app}

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