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Solve for $x$ for the following.

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W

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$\\var{n[0]}^x=\\var{n[1]}$

\n

\n

$x=$[[0]]

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$\\var{n[4]}^{\\var{Lowexpectations[0]}x}=\\var{n[5]}$

\n

\n

$x=$[[0]]

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$log_\\var{b[0]}(x)=\\var{p[0]}$

\n

$x=$[[0]]

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$log_\\var{b[2]}(\\var{Lowexpectations[1]}x)=\\var{p[2]}$

\n

$x=$[[0]]

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You will require the laws of logarithms:

\n

$\\log{a} + \\log{b} = \\log{ab}$

\n

$\\log{a} - \\log{b} = \\log{\\frac{a}{b}}$

\n

$\\log{a^n} = n\\log{a}$

\n

\n

(a)

\n

$\\log{\\var{a1}} + \\log{\\var{a2}} = \\log({\\var{a1}\\times\\var{a2}})=\\log{\\var{a1*a2}}$

\n

(b)

\n

$\\log{\\var{b1}} + \\log{\\var{b2}} = \\log({\\var{b1}\\times\\var{b2}})=\\log{\\var{b1*b2}}$

\n

(c)

\n

$\\log{\\var{c3}} - \\log{\\var{c2}} = \\log({\\var{c3}\\div\\var{c2}})=\\log{\\var{c3/c2}}$

\n

(d)

\n

$\\log{\\var{e1}} + \\log{\\var{e2}}+ \\log{\\var{e3}} = \\log({\\var{e1}\\times\\var{e2}\\times\\var{e3}})=\\log{\\var{e1*e2*e3}}$

\n

(e)

\n

$\\log{\\var{f1}} + \\log{\\var{f3}} - \\log{\\var{f5}} =  \\log({\\var{f1}\\times\\var{f3}\\div\\var{f5}})=\\log{\\var{f1*f3/f5}}$

\n

(f)

\n

$\\var{g1}\\log{\\var{g2}} + \\log{\\var{g3}} - \\log{\\var{g4}}= \\log({\\var{g2}^\\var{g1}\\times\\var{g3}\\div\\var{g4}})=\\log{\\var{g2^g1*g3/g4}}$

\n

(g)

\n

$\\frac{1}{2}\\log{\\var{h3}} - \\frac{1}{2}\\log{\\var{h2}}=\\frac{1}{2}(\\log{\\var{h3}} - \\log{\\var{h2}})= \\frac{1}{2} \\log({\\var{h3}\\div\\var{h2}})=\\frac{1}{2} \\log({\\var{h3/h2}})=\\log(\\var{h3/h2}^\\frac{1}{2})=\\log{\\var{(h3/h2)^0.5}}$

\n

(h)

\n

$\\log{\\var{i3}}-\\frac{1}{2}\\log{\\var{i4}} = \\log({\\var{i3}\\div\\var{i4}^\\frac{1}{2}})= \\log({\\var{i3}\\div\\var{i4^0.5}})=\\log{\\var{i3 / i4^0.5 }}$

\n

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You will require the laws of logarithms for these questions:

\n

$\\log{a} + \\log{b} = \\log{ab}$

\n

$\\log{a} - \\log{b} = \\log{\\frac{a}{b}}$

\n

$\\log{a^n} = n\\log{a}$

\n

\n

\n

Express each of the following as a single logarithm. 

\n

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$\\log{\\var{a1}} + \\log{\\var{a2}} = \\log$[[0]]

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$\\log{\\var{b1}} + \\log{\\var{b2}} = \\log$[[0]]

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$\\log{\\var{c3}} - \\log{\\var{c2}} = \\log$[[0]]

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$\\log{\\var{e1}} + \\log{\\var{e2}} + \\log{\\var{e3}} = \\log$[[0]]

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$\\log{\\var{f1}} + \\log{\\var{f3}} - \\log{\\var{f5}} = \\log$[[0]]

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$\\var{g1}\\log{\\var{g2}} + \\log{\\var{g3}} - \\log{\\var{g4}}=\\log$[[0]]

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$\\frac{1}{2}\\log{\\var{h3}} - \\frac{1}{2}\\log{\\var{h2}}=\\log$[[0]]

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$\\log{\\var{i3}}-\\frac{1}{2}\\log{\\var{i4}} = \\log$[[0]]

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Practice using the log rules to add and subtract logarithms

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Simplify the following expressions into single logs

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$log_a(\\var{n[2]})+log_a(\\var{n[3]})=log_a$([[0]])

\n

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$log_a(\\var{n[0]})+log_a(x)=log_a$([[0]])

\n

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$log_a(x)-log_a(\\var{n[1]})=log_a$([[0]])

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$\\var{n[5]}log_a(\\var{n[4]})=log_a$([[0]])

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Solve for x for the following equations

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$log_\\var{n[0]}(x)+log_\\var{n[0]}(\\var{n[1]})=\\var{n[2]}$

\n

\n

$x=$[[0]]

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$log_\\var{n[3]}(x)-log_\\var{n[3]}(\\var{n[4]})=log_\\var{n[3]}(\\var{n[5]})$

\n

\n

$x=$[[0]]

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$2log_\\var{n[6]}(\\var{n[7]})+log_\\var{n[6]}(x)=log_\\var{n[6]}(\\var{n[8]})+\\var{n[9]}$

\n

\n

$x=$[[0]]

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