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Nilai dari \\(\\dfrac{\\partial z}{\\partial x}\\) dari persamaan \\(yz=\\ln(x+z)\\) pada titik \\((x,y,z)=(1,\\var{b},0)\\) adalah \\(\\ldots\\).

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Misalkan linierisasi fungsi \\(f(x,y)=\\var{a}x^3+\\var{b}y^4+\\var{c}x^2y\\) di titik \\((1,1)\\) adalah \\(L(x,y)=Ax+By+C\\).

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Maka \\(A+B+C=\\ldots\\).

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Kurva ketinggian dari permukaan \\(z=\\dfrac{x^2+1}{x^2+y^2}\\) adalah sebagai berikut.

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\"\"

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Kurva berwarna merah menyatakan ketinggian untuk nilai \\(k=\\ldots\\).

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Pilihlah semua pasangan lintasan berikut untuk membuktikan \\(\\lim\\limits_{(x,y)\\to (1,0)}\\dfrac{xy-y}{(x-1)^2+y^2}\\) tidak ada.

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Diberikan fungsi \\(f(x,y)=x^3-6xy+8y^3\\).

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Jika $f_x(x,y)=Ax^2+By$ dan $f_y(x,y)=Cx+Dy^2$, maka $A+B+C+D=\\ldots$.

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Titik stasioner fungsi $f$ adalah $(0,0)$ dan $(x_0,y_0)$ dengan $x_0+y_0=\\ldots$.

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Tentukan $D(0,0)$ dan $f_{xx}(0,0)$ berturut-turut.

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Titik $(0,0)$ merupakan titik \\(\\ldots\\).

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Tentukan $D(x_0,y_0)$ dan $f_{xx}(x_0,y_0)$ berturut-turut.

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Titik $(x_0,y_0)$ merupakan titik \\(\\ldots\\).

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Waktunya 5 menit lagi ya.

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Selamat datang!

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Silakan gunakan set soal ini dengan bijak. Kalian bisa mencoba set soal ini terus-menerus.

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Set soal ini dapat digunakan oleh siapapun secara gratis.

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Petunjuk pengerjaan soal:

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Jika ada kunci jawaban yang salah, kalian dapat memberitahu kami di Instagram @meongmeongproject atau OA Line @eog7710d.

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