// Numbas version: exam_results_page_options {"name": "Set Soal Matematika IIC - Bab 13", "metadata": {"description": "", "licence": "None specified"}, "duration": 2700, "percentPass": 0, "showQuestionGroupNames": false, "showstudentname": true, "question_groups": [{"name": "PG + Isian", "pickingStrategy": "all-shuffled", "pickQuestions": 1, "questionNames": ["", "", "", ""], "questions": [{"name": "Mat 2C - Bab 13 - No 1", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Meong Meong Project", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4687/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "

Jika diberikan \\( f\\) merupakan medan skalar dan \\( \\mathbf{F} \\) suatu medan vektor, maka pernyataan berikut yang selalu benar adalah \\(\\ldots\\).

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Misalkan medan skalar \\( f \\) memenuhi \\( \\mathbf{F}=\\nabla f\\) dengan \\( \\mathbf{F}=(1+xy)e^{xy}\\,\\mathbf{i}+(e^y+x^2e^{xy})\\,\\mathbf{j} \\).

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Jika \\( f(0,0)=\\var{k} \\), maka \\(f(\\var{a},\\var{b})=\\ldots\\).

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Jika

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\\( \\displaystyle\\int_0^3\\int_0^{2x} w(x,y)\\, dy\\, dx+\\int_3^6\\int_0^{12-2x} w(x,y) \\, dy\\,dx =\\int_a^b\\int_{f(y)}^{g(y)} w(x,y)\\, dx\\,dy, \\)

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maka \\( a+b+f(\\var{a})+g(\\var{b})=\\ldots.\\)

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Usaha yang diperlukan untuk memindahkan objek pada lintasan \\( C: r(t)=t^2\\,\\mathbf{i}+\\sin t \\,\\mathbf{j}+t\\,\\mathbf{k}\\) untuk \\( 0\\leq t\\leq \\pi\\) jika terdapat medan vektor \\( \\mathbf{F}(x,y,z)=y^2\\cos(z)\\, \\mathbf{i}+2xy\\cos(z)\\, \\mathbf{j}-xy^2\\sin(z)\\, \\mathbf{k} \\) adalah $\\ldots$.

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Daerah \\( R \\) yang dibatasi oleh lintasan tertutup \\( C \\) akan mempunyai luas \\( A(R)=\\dfrac{1}{2}\\displaystyle\\oint_C (-y\\,dx+x\\,dy). \\) 

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Jika \\( C_1\\) menyatakan garis yang menghubungkan titik \\( (\\var{a},0) \\) ke titik \\( ({\\var{a+r}},\\var{b}) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_1} (-y\\,dx+x\\,dy) =\\) [[0]].

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Jika \\( C_2\\) menyatakan garis yang menghubungkan titik \\( ({\\var{a+r}},\\var{b}) \\) ke titik \\( (\\var{a},{\\var{a+r}}) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_2} (-y\\,dx+x\\,dy) =\\) [[1]].

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Jika \\( C_3\\) menyatakan garis yang menghubungkan titik \\( (\\var{a},{\\var{a+r}})  \\) ke titik  \\( (\\var{a},0) \\), maka \\( \\dfrac{1}{2}\\displaystyle\\int_{C_3} (-y\\,dx+x\\,dy) =\\) [[2]].

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Maka luas segitiga dengan titik sudut \\( (\\var{a},0) \\), \\( ({\\var{a+r}},\\var{b}) \\), dan \\( (\\var{a},{\\var{a+r}}) \\) adalah [[3]].

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Luas segilima dengan titik sudut \\( (\\var{a},0) \\), \\( ({\\var{a+r}},\\var{b}) \\), \\( (\\var{a},{\\var{a+r}}) \\), \\( (0,\\var{r+1}) \\), dan \\( (0,\\var{r}) \\) adalah \\(\\ldots\\).

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Waktunya 5 menit lagi ya.

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Selamat datang!

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Silakan gunakan set soal ini dengan bijak. Kalian bisa mencoba set soal ini terus-menerus.

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Set soal ini dapat digunakan oleh siapapun secara gratis.

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Petunjuk pengerjaan soal:

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Jika ada kunci jawaban yang salah, kalian dapat memberitahu kami di Instagram @meongmeongproject atau OA Line @eog7710d.

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