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Diketahui daerah \\(R=\\left\\{(x,y,z)\\bigg|\\dfrac{x}{\\sqrt{3}}\\leq y\\leq x,\\, x^2+y^2+z^2\\leq\\simplify{{a}^2},\\, x,y,z\\geq 0\\right\\}\\). 

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Jika \\(\\displaystyle \\iiint_{R} z \\,dV=\\frac{a\\pi}{192}\\), maka $a=\\ldots$.

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Diketahui $S$ merupakan belah ketupat yang titik-titik sudutnya \\((0,1)\\), \\((0,-1)\\), \\((\\var{a},0)\\), dan \\((-\\var{a},0)\\). 

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Dengan perubahan variabel yang tepat, integral \\(\\displaystyle \\iint_S (x+\\var{a}y)^3e^{x-\\var{a}y}\\,dA\\) akan sama dengan $\\ldots$.

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Diketahui \\(S\\) merupakan benda padat yang dibatasi oleh $z=\\var{a}-2x^2-2y^2$ dan $z=0$ serta $\\partial S$ adalah permukaan yang merupakan batas dari $S$. Diberikan medan vektor $\\mathbf{F}=4xz\\,\\mathbf{i}+(2-8xy^2)\\,\\mathbf{j}+(4z-2z^2)\\,\\mathbf{k}$. 

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Pilihlah seluruh pernyataan yang tepat.

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Misalkan $S$ merupakan permukaan \\(z=\\var{a}-3y+x^2\\) yang berada di atas segitiga dengan titik-titik sudut \\((0,0)\\), \\((2,0)\\), \\((2,-4)\\). 

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Jika \\(\\displaystyle \\iint_S z+3y-x^2\\,dS=\\frac{\\var{a}}{6}(a\\sqrt{a}-b\\sqrt{b})\\), maka \\(a-b=\\ldots\\).

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Diketahui $S$ merupakan benda pejal di atas bidang-$xz$ dan $y\\geq 0$ yang dibatasi oleh bola $x^2+y^2+z^2=\\simplify{{a}}^2$. Rapat massa benda pejal tersebut adalah \\(\\delta(x,y,z)=z\\sqrt{x^2+y^2+z^2}\\). 

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Dalam koordinat bola, daerah $S$ dapat dituliskan sebagai \\(S=\\{(\\rho,\\theta,\\varphi):0\\leq \\rho\\leq a, 0\\leq \\theta\\leq b\\pi, 0\\leq \\varphi\\leq c\\pi \\}\\) dengan $abc=\\ldots$.

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Masa benda pejal tersebut adalah $\\dfrac{A\\pi}{8}$ dengan $A=\\ldots$.

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Momen benda tersebut terhadap bidang-$xy$ adalah $\\dfrac{B\\pi}{12}$ dengan $B=\\ldots$.

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Waktunya 5 menit lagi ya.

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Selamat datang!

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Silakan gunakan set soal ini dengan bijak. Kalian bisa mencoba set soal ini terus-menerus.

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Set soal ini dapat digunakan oleh siapapun secara gratis.

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Petunjuk pengerjaan soal:

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Jika ada kunci jawaban yang salah, kalian dapat memberitahu kami di Instagram @meongmeongproject atau OA Line @eog7710d.

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