// Numbas version: exam_results_page_options {"name": "Limits using algebra", "metadata": {"description": "

Calculating limits using algebraic techniques

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Evaluate $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ax+b}{x^2+c} \\quad $ algebraically.

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate the $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ax+b}{x^2+c} \\quad $ algebraically.

", "advice": "

Use the difference of squares formula

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\\[ a^2 - b^2 = (a-b)(a+b) \\]

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to simplify the denominator.

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So, \\[ x^2-\\var{xlimsquared} =\\simplify{(x-{xlim})(x+{xlim})} \\] and the limit becomes

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\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{{x}-{xlim}}}{\\simplify{(x-{xlim})(x+{xlim})}} =  \\lim_{x\\to \\var{xlim}} \\frac{1}{\\simplify{(x+{xlim})}} = \\frac{1}{\\simplify{2*{xlim}}} \\]

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x limit

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Evaluate

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{x-{xlim}} }{x^2-\\var{xlimsquared}}.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

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Evaluate $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ax^2+bx+c}{ex+d} \\quad $ algebraically.

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ax^2+bx+c}{ex+d} \\quad $ algebraically.

", "advice": "

\n

Factorise the numerator to obtain

\n

\\[ \\lim_{x\\to \\var{anum}} \\frac{\\simplify{{knum}({x}-{anum})(x+{bnum})}}{\\simplify{(x-{anum})}} =\\lim_{x\\to \\var{anum}} \\var{knum}(\\simplify{x+{bnum}}) =\\simplify{{knum}*( {anum}+{bnum})}\\]

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a constant

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constant b

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bnum - anum

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anum x bnum

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constant k

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Evaluate

\n

\\[ \\lim_{x\\to \\var{anum}} \\frac{\\simplify{{knum}*x^2+{knum}*{bma}x-{knum}*{atb}} }{\\simplify{x-{anum}}}.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

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Evaluate $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ex+d}{ax^2+bx+c} \\quad $ algebraically.

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate $\\displaystyle \\quad \\lim_{x\\to a} \\frac{ex+d}{ax^2+bx+c} \\quad $ algebraically.

", "advice": "

\n

Factorise the denomenator to obtain

\n

\\[ \\lim_{x\\to \\var{bnum}} \\frac{\\simplify{(x-{bnum})}}{\\simplify{{knum}({x}-{bnum})(x+{anum})}} =\\lim_{x\\to \\var{bnum}} \\frac{1}{\\var{knum}(\\simplify{x+{anum}})} ={\\frac{1}{\\simplify{{knum}*({anum}+{bnum})}}}\\]

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a constant

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constant b

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bnum - anum

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anum x bnum

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constant k

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Evaluate

\n

\\[ \\lim_{x\\to \\var{bnum}} \\frac{\\simplify{x-{bnum}}}{\\simplify{{knum}*x^2+{knum}*-1*{bma}x-{knum}*{atb}} }.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

", "gaps": [{"type": "jme", "useCustomName": false, "customName": "", "marks": "2", "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": false, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "answer": "1/({knum}*({anum}+{bnum}))", "showPreview": true, "checkingType": "absdiff", "checkingAccuracy": 0.001, "failureRate": 1, "vsetRangePoints": 5, "vsetRange": [0, 1], "checkVariableNames": false, "singleLetterVariables": false, "allowUnknownFunctions": true, "implicitFunctionComposition": false, "valuegenerators": []}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always"}, {"name": "Use algebra to evaluate limit 5", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Wan Mekwi", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4058/"}], "tags": [], "metadata": {"description": "

Evaluate a rational limit using algebra

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate a rational limit using algebra

", "advice": "

Use the difference of squares formula

\n

\\[ a^2 - b^2 = (a-b)(a+b) \\]

\n

to simplify the denominator.

\n

So, \\[ x-\\var{xlim} = (\\sqrt{x}-\\sqrt{\\var{xlim}})(\\sqrt{x}+\\sqrt{\\var{xlim}}) \\] and the limit becomes

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\sqrt{x}-\\sqrt{\\var{xlim}}}{(\\sqrt{x}-\\sqrt{\\var{xlim}})(\\sqrt{x}+\\sqrt{\\var{xlim}})} =  \\lim_{x\\to \\var{xlim}} \\frac{1}{(x+\\sqrt{\\var{xlim}})} = \\frac{1}{2*\\sqrt{\\var{xlim}}} \\]

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x limit

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Evaluate

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\sqrt{x}-\\simplify{sqrt({xlim})} }{x-\\var{xlim}}.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

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Evaluate $\\displaystyle \\lim_{x\\to 0} \\frac{\\sqrt{ax+b} - d}{cx}$ using algebra

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate $\\displaystyle \\lim_{x\\to 0} \\frac{\\sqrt{ax+b} - d}{cx}$ using algebra

", "advice": "

Rationalise expression so that $x$ cancels.

\n

Note that $\\displaystyle \\frac{\\sqrt{\\simplify{{anum}*x+{bnum}}}-\\var{dnum}}{\\var{cnum}x} = \\frac{\\sqrt{\\simplify{{anum}*x+{bnum}}}-\\var{dnum}}{\\var{cnum}x}\\cdot \\frac{\\sqrt{\\simplify{{anum}*x+{bnum}}}+\\var{dnum}}{\\sqrt{\\simplify{{anum}*x+{bnum}}}+\\var{dnum}} = \\frac{\\simplify{{anum}*x+{bnum}} -\\simplify{{dnum}*{dnum}}}{\\var{cnum}x(\\sqrt{\\simplify{{anum}*x+{bnum}}}+\\var{dnum})}$.

\n

This simplifies to $\\displaystyle \\frac{\\var{anum}}{\\var{cnum}(\\sqrt{\\simplify{{anum}*x+{bnum}}}+\\var{dnum})}$.

\n

Hence,

\n

\\[ \\lim_{x\\to 0} \\frac{\\sqrt{\\simplify{{anum}*x+{bnum}}}-\\var{dnum}}{\\var{cnum}x} = \\lim_{x\\to 0} \\frac{\\var{anum}}{\\var{cnum}(\\sqrt{\\simplify{{anum}*x+{bnum}}}+\\var{dnum})} =  \\frac{\\var{anum}}{\\simplify{2*{cnum}*{dnum}}}. \\]

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constant a

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perfect square

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constant c

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Evaluate

\n

\\[ \\lim_{x\\to 0} \\frac{\\sqrt{\\simplify{{anum}*x+{bnum}}}-\\var{dnum} }{\\simplify{{cnum}*x}}.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

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Evaluate a rational limit using algebra

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate a rational limit using algebra

", "advice": "

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{{xlim}*x^{nnum}-x^{{nnum}+1}}}{\\sqrt{\\var{xlim}}-\\sqrt{x}}.\\]

\n

Start by factorising the numerator. 

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{x^{nnum}({xlim}-x)}}{\\sqrt{\\var{xlim}}-\\sqrt{x}}.\\]

\n

Then apply difference of squares  $a^2 - b^2 = (a-b)(a+b)$ to the second term in the numerator with $a=\\sqrt{\\var{xlim}}$ and $b=\\sqrt{x}$. This gives

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{x^{nnum}({xlim}-x)}}{\\sqrt{\\var{xlim}}-\\sqrt{x}} =\\lim_{x\\to \\var{xlim}} x^{\\var{nnum}}(\\sqrt{\\var{xlim}}+\\sqrt{x}). \\]

\n

We can now substitute the limit to obtain $\\simplify{2*sqrt({xlim})*{xlim}^{nnum}}$.

\n

PS: Remember to use the sqrt() command to enter radicals if you need to.

\n

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x limit

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Evaluate

\n

\\[ \\lim_{x\\to \\var{xlim}} \\frac{\\simplify{{xlim}*x^{nnum}-x^{{nnum}+1}}}{\\sqrt{\\var{xlim}}-\\sqrt{x}}.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

\n

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Evaluate $\\displaystyle \\lim_{x\\to k} \\frac{x+a}{\\sqrt{x+b} - c}$ using algebra

", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "

Evaluate $\\displaystyle \\lim_{x\\to k} \\frac{x+a}{\\sqrt{x+b} - c}$ using algebra

", "advice": "

Rationalise expression taking advantage of difference of squares formula $a^2-b^2=(a-b)(a+b)$.

\n

Note that $\\displaystyle \\frac{\\simplify{x-{anum}}}{\\sqrt{\\simplify{x+{dnum}}}-\\var{bnum}}=\\frac{\\simplify{x-{anum}}}{\\sqrt{\\simplify{x+{dnum}}}-\\var{bnum}}\\cdot\\frac{\\sqrt{\\simplify{x+{dnum}}}+\\var{bnum}}{\\sqrt{\\simplify{x+{dnum}}}+\\var{bnum}} = \\frac{(\\simplify{x-{anum}})({\\sqrt{\\simplify{x+{dnum}}}+\\var{bnum}})}{x+\\var{dnum}-\\var{bs}} $, which simplifies to ${\\sqrt{\\simplify{x+{dnum}}}+\\var{bnum}}$.

\n

Hence,

\n

\\[ \\lim_{x\\to \\var{anum}} \\frac{\\simplify{x-{anum}}}{\\sqrt{\\simplify{x+{dnum}}}-\\var{bnum} } = \\lim_{x\\to \\var{anum}} {\\sqrt{\\simplify{x+{dnum}}}+\\var{bnum}} = \\simplify{2*{bnum}}.\\]

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constant a

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constant b

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constant c

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b squared

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Evaluate

\n

\\[ \\lim_{x\\to \\var{anum}} \\frac{\\simplify{x-{anum}}}{\\sqrt{\\simplify{x+{dnum}}}-\\var{bnum} }.\\]

\n

giving your answer in exact form. 

\n

Answer: [[0]]

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