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Det er gitt en funksjon $f(x)=e^{\\var{k}x}$.

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Finn Taylor-polynomet av grad 4 til $f(x)$ i punktet $a=0$.

\n

$p_nf(x)=$ [[0]]  $+$ [[1]] $+$ [[2]] $+$ [[3]] $+$ [[4]]    

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Det er gitt en funksjon $f(x)=\\sin x$

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Grafen til $f(x)=\\sin x$ er tegnet i grønt, og grafen til Taylor-polynomet til $f$ av grad $n$ er tegnet i orange. For hver graf skal du avgjøre hva $n$ er. 

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Gitt en funksjon $f(x,y)=e^{\\var{a}x}\\cdot \\sin(\\var{b}y)$ og et punkt $a=\\Big(0,\\dfrac{\\pi}{2}\\Big) $

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Taylorpolynomet av grad 2 blir da

\n

$P_2(x,y)=$[[0]]$+$[[1]] $x+$[[2]]$(y-\\frac{\\pi}{2})+$[[3]]$x^2+$[[4]]$x(y-\\frac{\\pi}{2})+$[[5]]$(y-\\frac{\\pi}{2})^2$

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"useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "answer": "{a*b*cos(b*pi/2)}", "showPreview": true, "checkingType": "absdiff", "checkingAccuracy": 0.001, "failureRate": 1, "vsetRangePoints": 5, "vsetRange": [0, 1], "checkVariableNames": false, "singleLetterVariables": false, "allowUnknownFunctions": true, "implicitFunctionComposition": false, "caseSensitive": false, "valuegenerators": []}, {"type": "jme", "useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "answer": "{-b^2*sin(b*pi/2)}", "showPreview": true, "checkingType": "absdiff", "checkingAccuracy": 0.001, "failureRate": 1, "vsetRangePoints": 5, "vsetRange": [0, 1], "checkVariableNames": false, "singleLetterVariables": false, "allowUnknownFunctions": true, "implicitFunctionComposition": false, "caseSensitive": false, "valuegenerators": []}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always"}, {"name": "Taylorpolynom til e^x", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Ida Friestad Pedersen", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/792/"}, {"name": "Elena Malyutina", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/7213/"}, {"name": "Glen Wilson", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/21835/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "

Talylor-polynomet til $f$ av grad $n$ om punktet $a$ er

\n

$T_nf(x)=\\sum\\limits_{k=0}^n \\frac{f^{(0)}(a)}{k!}(x-a)^k$ og restledd $R_nf(x)=f(x)-T_nf(x)$.

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La $g(x)=e^x$ og $a=0$. Da

\n

$T_0e^x=$ [[0]]  og $T_0e^{0.2}=$ [[4]]

\n

$T_1e^x=$ [[1]]  og $T_1e^{0.2}=$ [[5]]

\n

$T_2e^x=$ [[2]]  og $T_2e^{0.2}=$ [[6]]

\n

$T_3e^x=$ [[3]]  og $T_3e^{0.2}=$ [[7]]  (avrund til 4 desimaler)

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true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "1.2", "maxValue": "1.2", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}, {"type": "numberentry", "useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "1.22", "maxValue": "1.22", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, 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Regn ut med kalkulator $e^{0.2}$ = [[0]]  (avrund til 4 desimaler)

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La $g(x)=e^x$ og $a=0$, som over. Da er

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$R_0e^x=$ [[0]] (avrund til 4 desimaler).

\n

$R_1e^x=$ [[1]] (avrund til 4 desimaler).

\n

$R_2e^x=$ [[2]] (avrund til 4 desimaler).

\n

$R_3e^x=$ [[3]] (avrund til 4 desimaler).

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For hvilken naturlige tall $n$ er $\\lvert R_ne^x(.2) \\rvert $ mindre enn $10^{-6}=.000001$?  

\n

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La $f(x)=\\dfrac{1}{1-x}$

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La oss finne Taylorrekka til $f(x)$ i $x=0$

\n

$f(0)=$ [[0]]

\n

$f'(x)=$ [[1]]         $f'(0)=$ [[2]]       $\\dfrac{f'(0)}{1!}=$ [[2]]

\n

$f''(x)=$ [[3]]         $f''(0)=$ [[4]]       $\\dfrac{f''(0)}{2!}=$ [[5]]

\n

$f'''(x)=$ [[6]]         $f'''(0)=$ [[7]]       $\\dfrac{f'''(0)}{3!}=$ [[8]]

\n

$f^{(n)}(x)=$ [[9]]         $f^{(n)}(0)=$ [[10]]       $\\dfrac{f^{(n)}(0)}{n!}=$ [[11]]

\n

$Tf(x)=\\sum\\limits_{n=0}^{\\infty}$ [[12]]

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false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "answer": "x^n", "showPreview": true, "checkingType": "absdiff", "checkingAccuracy": 0.001, "failureRate": 1, "vsetRangePoints": 5, "vsetRange": [0, 1], "checkVariableNames": false, "singleLetterVariables": false, "allowUnknownFunctions": true, "implicitFunctionComposition": false, "valuegenerators": [{"name": "n", "value": ""}, {"name": "x", "value": ""}]}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always"}, {"name": "Taylorrekke til f(x)", "extensions": [], "custom_part_types": [], "resources": [["question-resources/formula.PNG", "/srv/numbas/media/question-resources/formula.PNG"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Elena Malyutina", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/7213/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "

Hvilke av følgende funksjoner $f(x)$ er lik sin Taylorrekke $Tf(x)$ for alle $x$

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Det er gitt en følge $\\{a_n\\}$ slik at $a_n=\\var{a}n+\\var{b}$ og rekken $\\sum\\limits_{n=0}^{\\infty}a_n$ er generert av følgen $\\{a_n\\}$.

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Skriv inn de delsummene 

\n

$S_0$=[[0]]

\n

$S_1$=[[1]]

\n

$S_2$=[[2]]

\n

$S_3$=[[3]]

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Det er gitt en rekke $\\sum\\limits_{n=0}^{\\infty}a_n$ , der $a_n\\geq0$ for alle $n$.

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Velg riktige påstander

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Det er gitt en geometrisk rekke $\\sum\\limits_{k=0}^{\\infty}a_0r^k$

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Match påstandene med betingelsene på $r$

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Det er gitt en rekke $\\sum\\limits_{n=0}^{\\infty}\\frac{n+1}{2n^2+2}$.

\n

Vi regner ut at $\\lim\\limits_{n\\rightarrow\\infty}\\dfrac{\\frac{n+1}{2n^2+2}}{\\frac{1}{n}}=\\lim\\limits_{n\\rightarrow\\infty}\\dfrac{n^2+n}{2n^2+2}=\\frac{1}{2}$

\n

Videre vet vi at at rekken $\\sum\\limits_{n=0}^{\\infty}\\frac{1}{n}$ divergerer.

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Hva kan vi da si om rekken $\\sum\\limits_{n=0}^{\\infty}\\frac{n+1}{2n^2+2}$?

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Det er gitt to rekker $\\sum\\limits_{n=0}^{\\infty}a_n$ og $\\sum\\limits_{n=107}^{\\infty}a_n$

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Velg riktige påstander

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Hvilke av følgende funksjonsfølger konvergerer punktvis mot $e^x$ når $n\\rightarrow\\infty$?

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La $\\{f_n(x)\\}, f(x): A\\subseteq\\mathbb{R}\\rightarrow\\mathbb{R}$.

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Velg rigtig påstand

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For rekken $\\sum\\limits_{n=1}^{\\infty}\\frac{1}{n}$ ser vi at $\\lim\\limits_{n\\rightarrow\\infty}a_n=\\lim\\limits_{n\\rightarrow\\infty}\\frac{1}{n}=0$

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Hvilken påstand er da riktig?

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Det er gitt to positive rekker $\\sum\\limits_{n=0}^{\\infty}a_n$ og $\\sum\\limits_{n=0}^{\\infty}b_n$ slik at $a_n\\geq b_n$ for alle $n$. 

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Velg riktige påstander

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Det er gitt to geometriske rekker $\\sum\\limits_{n=0}^{\\infty}\\frac{1}{\\var{a}^n}$ og $\\sum\\limits_{n=0}^{\\infty}\\frac{1}{\\var{b}^n}$ med kvotienter $r=\\frac{1}{\\var{a}}$ og $r=\\frac{1}{\\var{b}}$ henholdsvis.

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Bruk formelen $\\sum\\limits_{n=0}^{\\infty}r^na_0=\\frac{a_0}{1-r}$ for $|r|<1$ og finn

\n

$\\sum\\limits_{n=0}^{\\infty}\\frac{1}{\\var{a}^n}$=[[0]]

\n

$\\sum\\limits_{n=0}^{\\infty}\\frac{1}{\\var{b}^n}$=[[1]]

\n

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Finn videre

\n

$\\sum\\limits_{n=0}^{\\infty}\\Big(\\frac{1}{\\var{a}^n}+\\frac{1}{\\var{b}^n}\\Big)=$[[0]]

\n

$\\sum\\limits_{n=0}^{\\infty}\\Big(\\frac{1}{\\var{a}^n}-\\frac{1}{\\var{b}^n}\\Big)=$[[1]]

\n

$\\sum\\limits_{n=0}^{\\infty}\\Big(\\frac{1}{\\var{a}^n}\\cdot\\frac{1}{\\var{b}^n}\\Big)=$ [[2]]

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