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Basic circuit analysis questions

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These are basic circuit analysis questions and can be used for year 1 introductory classes to circuit analysis.

", "licence": "All rights reserved"}, "statement": "

A component has 3 A of current flowing through it for 20 seconds.  

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a) The total amount of current that passes through the component is, $Q = I \\times t$. Therefore, $Q = 3 \\times 20 = 60$ C.

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b) The potential difference across the component is, $V = \\frac{W}{Q}$. Therefore, $V = \\frac{120}{60} = 2$ V.

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c) The resistance of the component is, $R =\\frac{V}{I} = \\frac{2}{3} = 0.67 \\Omega$ . 

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What is the total amount of charge, in Coulombs (C), that passes through the component during this time?

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[[0]] C 

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The total work done in moving all the charges that had passed in 20 seconds is 120 J. What is the potential difference across the component in Volts (V)?

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[[0]] V

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What is the resistance of the component in Ohms $\\Omega$? Give your answer to 2 decimal places.

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[[0]]$\\Omega$

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Basic Circuit Analysis questions

", "licence": "All rights reserved"}, "statement": "

The following plots show the I-V characteristic of different types of circuit components. 

", "advice": "

a) For an ohmic conductor $ I \\propto V$. Hence the gradient must be constant, in other words, the graph is a straight line passing through the origin. There is only one option that satisfies this requirement.

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b) The gradient of the I-V characteristic is, $Gradient = \\frac{I}{V} = \\frac{1}{R}$. Therefore, $R = \\frac{1}{Gradient} = 5 \\Omega$.

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Which of the following graphs show the I-V relationship of an ohmic conductor?

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Given that the gradient of the I-V curve of an ohmic conductor is 0.2 $\\Omega^{-1}$. What is the resistance of the conductor in Ohms ($\\Omega$)?

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Basic circuit analysis

", "licence": "All rights reserved"}, "statement": "

Analyse the current in the branches using Kirchoff's laws. 

", "advice": "

a) Using Kirchoff's 1st Law: \\[Total\\:I_{in} = Total\\:I_{out}\\\\ 2\\,A +1\\,A = I_{out} + 0.5\\,A\\\\ I_{out} = 2.5\\,A\\]

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b) The potential difference across all the parallel branches are the same. Therefore, we can write:\\[I_0\\,R = 2I_1\\,R\\:\\text{and}\\:I_0\\,R= 6I_2\\,R\\\\\\ I_0 = 2I_1\\:\\text{and}\\:I_0=6I_2\\]. 

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Using Kirchoff's first law at the first junction we can obtain the following relation:\\[I_0+I_1+I_2=3\\,A\\\\ I_0 + \\frac{1}{2}I_0 + \\frac{1}{6}I_0=3\\,A\\ \\\\ \\frac{10}{6}I_0=3\\,A\\\\ I_0=1.8\\,A\\].

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Therefore, $I_1 = \\frac{1}{2}\\times1.8=0.9\\,A$ and $I_2=\\frac{1}{6}\\times1.8=0.3\\,A$.

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Determine the unknown current, Iout, using Kirchoff's 1st Law. 

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[[0]] A

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Determine the three unknown currents, $I_0,\\,I_1\\,\\text{and}\\,I_2$., in Amperes (A)

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$I_0=$[[0]]A, $I_1=$ [[1]] A and $I_2=$[[2]] A. 

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