// Numbas version: finer_feedback_settings
{"name": "FIS5047_S8_Numbas", "metadata": {"description": "", "licence": "None specified"}, "duration": 0, "percentPass": 0, "showQuestionGroupNames": false, "shuffleQuestionGroups": false, "showstudentname": true, "question_groups": [{"name": "Group", "pickingStrategy": "all-ordered", "pickQuestions": 1, "questionNames": ["", "", "Aplicacion Faraday", ""], "variable_overrides": [[], [], [], []], "questions": [{"name": "Faraday", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Diana Amaro", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4562/"}, {"name": "Ivan Munoz", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/18334/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "<p><span style=\"vertical-align: inherit;\">Conectar un galvan&oacute;metro $G$ (dispositivo que indica el paso de corriente el&eacute;ctrica) a una bobina $B$ (hilo conductor enrollado en espiral) e introducir a lo largo de esta bobina se coloca una barra magnetizada $M$. Inmediatamente se mueve la aguja del galvan&oacute;metro, comprob&aacute;ndose as&iacute; que el alambre es atravesado por una corriente el&eacute;ctrica, aunque en el conjunto no hay bater&iacute;a ni generador de ning&uacute;n tipo. El simple movimiento de la barra imantada da origen a la corriente el&eacute;ctrica. Solo hay corriente el&eacute;ctrica en el alambre cuando la barra se mueve. Si la barra se detiene, la aguja del galvan&oacute;metro vuelve inmediatamente a cero.</span></p>\n<p><span style=\"vertical-align: inherit;\">De la experiencia descrita en el texto, se concluye que;</span></p>", "advice": "", "rulesets": {}, "builtin_constants": {"e": true, "pi,\u03c0": true, "i": true}, "constants": [], "variables": {}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": [], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "1_n_2", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minMarks": 0, "maxMarks": 0, "shuffleChoices": false, "displayType": "radiogroup", "displayColumns": 0, "showCellAnswerState": true, "choices": ["<pre class=\"tw-data-text tw-text-large tw-ta\" data-placeholder=\"Traducci&oacute;n\" id=\"tw-target-text\" dir=\"ltr\"><span class=\"Y2IQFc\" lang=\"es\">Un campo el&eacute;ctrico siempre crea un campo magn&eacute;tico.</span></pre>", "Un campo magn&eacute;tico siempre genera una corriente el&eacute;ctrica.", "Una corriente el&eacute;ctrica puede crear un campo magn&eacute;tico", "Una barra magnetizada en movimiento puede generar una corriente el&eacute;ctrica."], "matrix": [0, 0, 0, "5"], "distractors": ["", "", "", ""]}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "type": "question"}, {"name": "Circuito 1", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Ivan Munoz", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/18334/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "<p>Un componente tiene 3 A de corriente que fluye a trav&eacute;s de &eacute;l durante 20 segundos.</p>", "advice": "<p>a) La cantidad total de corriente que pasa a trav&eacute;s del componente es $Q=I\\cdto t$. Por lo tanto, $Q=3&times;20=60 C.$</p>\n<p>b) La diferencia de potencial a trav&eacute;s del componente es, $V=WQ$. Por lo tanto, $V=\\frac{120}{60}=2 V$.</p>\n<p>c) La resistencia del componente es, $R=\\frac{V}{I}=\\frac{2}{3}=0.67\\Omega$.</p>", "rulesets": {}, "builtin_constants": {"e": true, "pi,\u03c0": true, "i": true}, "constants": [], "variables": {}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": [], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "<p>&iquest;Cu&aacute;l es la cantidad total de carga, en Coulombs(C), que pasa a trav&eacute;s del componente durante este tiempo?</p>\n<p>[[0]]C</p>\n<p></p>", "gaps": [{"type": "numberentry", "useCustomName": true, "customName": "Carga", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "60-1", "maxValue": "60+1", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "sortAnswers": false}, {"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "<p>El trabajo total realizado al mover todas las cargas que hab&iacute;an pasado en 20 segundos es de 120 J. &iquest;Cu&aacute;l es la diferencia de potencial entre los componentes en voltios (V)?</p>\n<p></p>\n<p>[[0]]J</p>", "gaps": [{"type": "numberentry", "useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "2", "maxValue": "2", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "sortAnswers": false}, {"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "<p>&iquest;Cu&aacute;l es la resistencia del componente en ohmios &Omega;? Da tu respuesta con 2 decimales.</p>\n<p></p>\n<p style=\"text-align: center;\">[[0]]$\\Omega$</p>", "gaps": [{"type": "numberentry", "useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "0.67*0.95", "maxValue": "0.67*1.05", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "type": "question"}, {"name": "Faraday Ej", "extensions": [], "custom_part_types": [], "resources": [["question-resources/Prob141.jpg", "/srv/numbas/media/question-resources/Prob141.jpg"], ["question-resources/riel_barra.JPG", "/srv/numbas/media/question-resources/riel_barra.JPG"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Ivan Munoz", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/18334/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "<p>Considere el riel de la figura, formado por dos alambres conductores.<br/>La barra de masa $m=${m} kg tiene resistencia $R=${R} $\\Omega$ y desliza libremente. <br/>El campo magn&eacute;tico uniforme $\\vec{B}=${B}T act&uacute;a vertical hacia arriba. $L=${L} es la distancia entre los alambres y $\\varepsilon=$ {ep} $V$ es la fem del circuito <br/><br/><img src=\"resources/question-resources/riel_barra.JPG\"/><br/>Asuma que la barra se mueve con velocidad $v=${v} m/s</p>", "advice": "<p>La fem externa producir&aacute; una corriente que pasar&aacute; por la barra que posee corriente $R$.</p>\n<p>Como hay corriente en la barra, el campo magn&eacute;tico externo afectar&aacute; a la barra. La barra al moverse el flujo magn&eacute;tico a trav&eacute;s del loop variara, generando una fem inducida. El flujo a trav&eacute;s del loop formado por los rieles y la barra es, <br/>$\\Phi_B=\\int_S \\vec{B}\\cdot d\\vec{S}=BS=BLx.$</p>\n<p>La variaci&oacute;n del flujo ser&aacute;<br/>$\\dfrac{d\\Phi_B}{dt}=BL\\dot{x}=BLv(t)$</p>\n<p>donde $v(t)$ es la velocidad de la barra.</p>\n<p>Por ley de Lenz, la fem inducida, <br/>$\\varepsilon_{\\text{ind}}=-BLv$.</p>\n<p>Usando leyes de Kirchhoff al circuito visto desde arriba, escogeremos la corriente en sentido anti-horario, por lo que <br/>$\\varepsilon+\\varepsilon_{\\text{ind}}-IR=0\\Rightarrow \\varepsilon-BLv=IR$</p>\n<p>Por lo tanto, <br/>$I=\\dfrac{\\varepsilon}{R}-\\dfrac{BLv}{R}.$</p>", "rulesets": {}, "builtin_constants": {"e": true, "pi,\u03c0": true, "i": true}, "constants": [], "variables": {"b": {"name": "b", "group": "Ungrouped variables", "definition": "random(1 .. 10#1)", "description": "", "templateType": "randrange", "can_override": false}, "l": {"name": "l", "group": "Ungrouped variables", "definition": "random(1 .. 3#1)", "description": "", "templateType": "randrange", "can_override": false}, "m": {"name": "m", "group": "Ungrouped variables", "definition": "random(1 .. 5#1)", "description": "", "templateType": "randrange", "can_override": false}, "r": {"name": "r", "group": "Ungrouped variables", "definition": "random(1 .. 5#1)", "description": "", "templateType": "randrange", "can_override": false}, "ep": {"name": "ep", "group": "Ungrouped variables", "definition": "random(1 .. 10#1)", "description": "", "templateType": "randrange", "can_override": false}, "v": {"name": "v", "group": "Ungrouped variables", "definition": "random(1 .. 6#1)", "description": "", "templateType": "randrange", "can_override": false}}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": ["b", "l", "m", "r", "ep", "v"], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "<p>Obtenga la corriente que fluye por el circuito</p>\n<p></p>\n<p>$I=$[[0]]</p>", "gaps": [{"type": "numberentry", "useCustomName": true, "customName": "corriente", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "(ep/r-b l v/r)*0.95", "maxValue": "(ep/r-b l v/r)*1.05", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "type": "question"}, {"name": "Ley de Ampere", "extensions": [], "custom_part_types": [], "resources": [["question-resources/ampere.png", "/srv/numbas/media/question-resources/ampere.png"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Ivan Munoz", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/18334/"}], "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "<p>Considere un alambre muy largo. Considere que por el alambre pasa una corriente $I=${II}A</p>", "advice": "<p>Consideremos un cable recto por el que pasa una corriente constante $I$. Entonces, de la ley de Ampere, escogeremos como l&iacute;nea Amperiana un circulo de radio $r$ al rededor del cable.</p>\n<p></p>\n<p><img src=\"resources/question-resources/ampere.png\"/></p>\n<p>Entonces, de la ley de Ampere tendremos,</p>\n<p></p>\n<p>$\\int B dl=B(r) (2 \\pi r)=\\mu_0 I_{enc}$</p>\n<p>Donde usamos que estamos cerrando la l&iacute;nea amperiana en un c&iacute;rculo por lo que tendremos el perimetro de un c&iacute;rculo ($2 \\pi r$).</p>\n<p>Por lo tanto $B(r)=\\frac{\\mu_0}{2\\pi r} I_{enc}$</p>\n<p></p>\n<p>Como la corriente es constante, la corriente encerrada sera $I_{enc}=I$.</p>\n<p></p>\n<p></p>", "rulesets": {}, "builtin_constants": {"e": true, "pi,\u03c0": true, "i": true}, "constants": [], "variables": {"d": {"name": "d", "group": "Ungrouped variables", "definition": "random(1 .. 5#1)", "description": "", "templateType": "randrange", "can_override": false}, "mu": {"name": "mu", "group": "Ungrouped variables", "definition": "0.00000125", "description": "", "templateType": "number", "can_override": false}, "ii": {"name": "ii", "group": "Ungrouped variables", "definition": "random(1 .. 4#1)", "description": "", "templateType": "randrange", "can_override": false}}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": ["d", "mu", "ii"], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "<p>Obtenga el campo magn&eacute;tico a una distancia $r=${d} m del cable.</p>\n<p></p>\n<p>$B=$[[0]] T</p>", "gaps": [{"type": "numberentry", "useCustomName": false, "customName": "", "marks": 1, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "minValue": "mu II /( 2 pi d)*0.95", "maxValue": "mu II/(2 pi d)*1.05", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "sortAnswers": false}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "type": "question"}]}], "allowPrinting": true, "navigation": {"allowregen": true, "reverse": true, "browse": true, "allowsteps": true, "showfrontpage": true, "showresultspage": "oncompletion", "navigatemode": "sequence", "onleave": {"action": "none", "message": ""}, "preventleave": true, "startpassword": ""}, "timing": {"allowPause": true, "timeout": {"action": "none", "message": ""}, "timedwarning": {"action": "none", "message": ""}}, "feedback": {"showactualmark": true, "showtotalmark": true, "showanswerstate": true, "allowrevealanswer": true, "advicethreshold": 0, "intro": "", "end_message": "", "reviewshowscore": true, "reviewshowfeedback": true, "reviewshowexpectedanswer": true, "reviewshowadvice": true, "feedbackmessages": [], "enterreviewmodeimmediately": true, "showexpectedanswerswhen": "inreview", "showpartfeedbackmessageswhen": "always", "showactualmarkwhen": "always", "showtotalmarkwhen": "always", "showanswerstatewhen": "always", "showadvicewhen": "inreview"}, "diagnostic": {"knowledge_graph": {"topics": [], "learning_objectives": []}, "script": "diagnosys", "customScript": ""}, "type": "exam", "contributors": [{"name": "Ivan Munoz", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/18334/"}], "extensions": [], "custom_part_types": [], "resources": [["question-resources/Prob141.jpg", "/srv/numbas/media/question-resources/Prob141.jpg"], ["question-resources/riel_barra.JPG", "/srv/numbas/media/question-resources/riel_barra.JPG"], ["question-resources/ampere.png", "/srv/numbas/media/question-resources/ampere.png"]]}