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Consider the following question:
\n\nFind a solution to $x^2-5x=0$. | \n
All of the answers are correct. Answers A and B are probably the best because there is no need to find all solutions.
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B $0^2-5(0)=0$ so $x=0$ is a solution.
C Factorise $x^2-5x=0$ to get $x(x-5)=0$. This implies that $x=0$ or $x=5$.
D $0^2-5(0)=0$ and $5^2-5(5)=0$ so $x=0$ and $x=5$ are solutions.
Consider the following question:
\n\nShow that $x=5$ is a solution to $x^2-5x=0$. | \n
A, C and D are correct. Answer A is probably the best because there is no need to find other solutions.
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B $0^2-5(0)=0$ so $x=0$ is a solution.
C Factorise $x^2-5x=0$ to get $x(x-5)=0$. This implies that $x=0$ or $x=5$.
D $0^2-5(0)=0$ and $5^2-5(5)=0$ so $x=0$ and $x=5$ are solutions.
Consider the following question:
\n\nSolve $x^2-5x=0$. | \n
C is the best answer. Answers A and B are missing one of the possible solutions. D has found all the solutions, so it is correct, but not as good as C because it doesn't explain how the solutions were found or why they are the only solutions possible.
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B $0^2-5(0)=0$ so $x=0$ is a solution.
C Factorise $x^2-5x=0$ to get $x(x-5)=0$. This implies that $x=0$ or $x=5$.
D $0^2-5(0)=0$ and $5^2-5(5)=0$ so $x=0$ and $x=5$ are solutions.
A student solved the following multi-part question:
\n\n\n (a) Factorise the expression $x^2-5x$. \n(b) Hence, or otherwise, solve $x^2-5x=0$. \n | \n
\n (a) $x(x-5)$ \n(b) $x=\\frac{-b \\pm \\sqrt{b^2-4ac}}{2a}=\\frac{5 \\pm \\sqrt{25}}{2}=0$ or $5$. \n | \n
D is correct. The student didn't use the idea from part (a) which would have made the solution easier.
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", "B The students answer to part (b) was a 'hence' answer because they didn't make use of the earlier part.
", "C The students answer to part (b) was an 'otherwise' answer because they did make use of the earlier part.
", "D The students answer to part (b) was an 'otherwise' answer because they didn't make use of the earlier part.
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\n\n\n (a) Factorise the expression $x^2-5x$. \n(b) Hence, or otherwise, solve $x^2-5x=0$. \n | \n
\n (a) $x(x-5)$ \n(b) $x(x-5)=0$, so $x=0$ or $5$. \n | \n
A is correct. The student used the idea from part (a) which made the solution easier.
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", "C The students answer to part (b) was an 'otherwise' answer because they did make use of the earlier part.
", "D The students answer to part (b) was an 'otherwise' answer because they didn't make use of the earlier part.
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