HELM book 2.1.2 exercises
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\nUnmarked: Answer: \"The argument is the input.\"
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", "advice": "The argument is the input.
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", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Given the function $\\var{fe}(\\var{ve})=\\var{expr}$ find $\\var{fe}(\\var{c[2]})$
", "advice": "$\\var{fe}(\\var{ve})=\\var{expr}$
\n$\\var{fe}(\\var{c[2]})=(\\var{c[0]})(\\var{c[2]})\\var{latex(sgn)}\\var{abs(c[1])}=\\var{ans}$
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", "advice": "Given $\\var{fe}(\\var{ve})=\\var{fn}$
\n$\\displaystyle{\\var{fe}(\\var{vale})= \\var{c[0]}(\\var{vale})^2\\var{latex(sgn)}\\var{abs(c[1])}=\\var{ans}}$
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\n(a) $\\displaystyle{f(x+h)= \\var{ans1}}$
\n(b) $\\displaystyle{f(x+h)-f(x) = \\var{ans2} = \\var{ans2sim} }$
\n(b) $\\displaystyle{f(x+h)-f(x) = \\var{ans2} = \\var{ans2bits} = \\var{ans2sim} }$
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", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Given $\\displaystyle{f(x)=\\frac{1}{(\\var{a}-x)^2}}$, evaluate $\\displaystyle{ f\\left( \\frac{x}{\\var{ve}}\\right) }$
", "advice": "\\[\\begin{align*} f\\left( \\frac{x}{\\var{ve}}\\right)&= \\var{ans}\\\\ &= \\frac{1}{\\var{a}^2-2\\times\\var{a}\\frac{x}{\\var{ve}}+\\frac{x^2}{\\var{ve}^2} }\\\\&=\\frac{1}{\\frac{\\var{ve}^2\\var{a}^2-\\var{2*a}\\var{ve}x+x^2}{\\var{ve}^2}}\\\\&=\\frac{\\var{ve}^2}{\\var{a^2}\\var{ve}^2-\\var{2*a}\\var{ve}x+x^2}\\end{align*}\\]
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\nQuestions generally have multiple versions, clicking the \"Try another question like this one\" button will generate a new version.
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