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Originally put together for EG4140/50 group UEL, 2015.

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You have 5 minutes left to complete this test.

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Recall that, for instance, adding  $-3$ is the same as subtracting $3$ and that $-3 \\times -4 = 12$

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See the following pages for further examples and some explanations of why this makes sense.

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http://www.mathsisfun.com/positive-negative-integers.html

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http://www.mathsisfun.com/multiplying-negatives.html

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$(\\var{a}) + (\\var{b})$

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[[0]]

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$\\var{d} \\times (\\var{c})$

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[[0]]

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$(\\var{b}) \\times (\\var{c})$

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[[0]]

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$ \\var{f} \\div 5$

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(Give your answer as a decimal.)

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[[0]]

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$\\dfrac{\\var{c}}{-5}$.

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(Give your answer as a decimal.)

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[[0]]

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Find the value of the following:

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Testing addition, multiplication and division involving negative numbers.

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This interactive Algebra Refresher Booklet provides help and practice with algebra.

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${(\\simplify {t  + {a}})^2}$   and   $ t^2 + \\var{asq}$

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Yes, the expressions are equivalent.

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No, the expressions will not always take the same value.

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$ \\var{b}(\\simplify{t + {c}})$ and $\\var{b}t +\\var{c}$

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Yes, the expressions are equivalent.

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No, the expressions will not always have the same value.

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$ \\dfrac { \\var{d}t - \\var{f}}{\\var{g}}$ and $ \\var{h}t - \\var{j}$

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Yes, the expressions are equivalent.

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No, the expressions will not always take the same value.

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Two algebraic expressions are equivalent if they take the same value whatever the value of the variable (in this case $t$).

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Are the following pairs of expressions equivalent?

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True/false questions on multiplying brackets and dividing an expression by a number.

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For $\\var{p}-t \\  \\var{inequal} \\ \\var{q}$, the easiest way to start is to add $t$ to both sides of the inequality.

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This will give you $ \\var{p} \\ \\var{inequal} \\ t \\ + \\ \\var{q} $.

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Now subtracting $ \\var{q} $ from both sides gives $ t \\ \\var{ansinequal} \\var{diff} $

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These online resources might help you revise this topic.

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http://www.mathsisfun.com/algebra/inequality-solving.html

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http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html

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$\\var{p}-t \\  \\var{inequal} \\ \\var{q}$

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Input the  appropriate  inequality sign, either < or >, in the first box and the correct range in the second.

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$t\\;\\;$ [[0]]$\\;\\;$ [[1]]

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Find the range of values of $t$ which satisfy the following inequality.

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Solve $p - t < \\text{or}> q$

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A general method is to make the coefficients of either $x$ or $y$ equal by multiplying one or both equations by a constant.

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You can then add or subtract the resulting equations to get an equation in just $x$ or $y$, which you can solve.

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The value of the other variable can be found by substitution into one of the original equations.

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See the following link for more explanation and some worked examples:

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http://www.mathcentre.ac.uk/resources/uploaded/mc-bus-simult-2009-1.pdf.

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$x=$ [[0]]

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$y=$ [[1]]

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Input your answers as fractions (use the '/' key) and not as decimals.

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Input your answer as a fraction and not a decimal.

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Input your answer as a fraction and not as a decimal.

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Solve:

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\\[\\begin{eqnarray*} \\simplify{{a}x+{b}y}&=&\\var{c}\\\\\\\\\\simplify{{a1}x+{b1}y}&=&\\var{c1}\\end{eqnarray*}\\]

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Shows how to define variables to stop degenerate examples.

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Remember that you need to treat both sides of the equation in exactly the same way.

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Given $ \\simplify  {n/{a} + {s}*{b} = {c} } $,

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your first step could be to $ \\var{op} \\ \\  \\var{b}$ $ \\ \\ \\var{fromto}$ both sides, giving you $ \\simplify { n/{a} = {c} - {s}*{b}}$.

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Then multiplying both sides by $ \\var{a}$ will give $ \\simplify{ n= {a}*({c}-{s}*{b})}$.

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If you decide to multiply by $\\var{a}$ first, you need to be careful to multiply all of the terms by $\\var{a}$ giving

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$ \\simplify{ n +{s}*{b}*{a} = {c}*{a}}$.

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For some general advice on solving equations see http://www.mathsisfun.com/algebra/equations-solving.html

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If $ \\simplify{{n}/{a} + {s}* {b} = {c}}  $, enter the value of $n$ in the space below.

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$n= $ [[0]]

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Solve the following equation to find the value of $n$.

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Chosen so that c>b to avoid negative answers.

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Simple Linear Equation.

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$ \\dfrac{n}{a} \\pm b = c$

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You need to check in which order your calculator carries out the operations.

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If, when you input $2+3 \\times 4$ you get the answer $14$, then your calculator is scientific and will perform multiplication and division before addition and subtraction. If you get the answer $20$ then your calculator is performing operations in the order written.

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Be careful with negative numbers. Remember that squaring a negative number gives a positive number. For instance if you are using your calculator to find the square of $-6$ you need to input $(-6)^2$, not $-6^2$.

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$a + b c$

\n

[[0]]

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$ b ^2 - \\sqrt{c}$

\n

[[0]]

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$ \\dfrac{c^3 -a}{b+ a}$

\n

[[0]]

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If $a = \\var{a}, \\ b= \\var{b}$ and  $c= \\var{c}$, use your calculator to work out the value of the following expressions. Round your answer to 2 d. p. where necessary.

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Understanding order of operations on a calculator and using power and root keys.

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