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Multiply two numbers in standard form, then divide two numbers in standard form.

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Simplify, leaving the result in standard index form.

", "advice": "

We use the rules for multiplying and dividing powers.

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To multiply powers we add, for example $10^2 \\times 10^6 = 10^{(2+6)} = 10^{8}$.

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To divide powers we subtract, for example $10^2 \\div 10^6 = 10^{(2-6)} = 10^{-4}$.

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a)

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\\[ \\begin{align} (\\var{int} \\times 10^\\var{ran - 3} ) \\times (\\var{int - 11} \\times 10^\\var{ran})  &= \\var{int} \\times (\\var{int-11}) \\times 10^{(\\var{ran - 3} + \\var{ran})} \\\\&= (\\var{int*(int-11)}) \\times 10^{\\var{ran - 3 + ran}} \\end{align} \\]

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We want to write this number in standard form so we move decimal place one place to the left to get

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\\[(\\var{int*(int-11)/10}) \\times 10^{(\\var{ran - 3 + ran} + 1)} = (\\var{int*(int-11)/10}) \\times 10^{\\var{ran - 2 + ran}} \\text{.}\\]

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b)

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Similarly,

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\\[ \\begin{align} (\\var{int*int} \\times 10^\\var{ran -4} ) \\div (\\var{int} \\times 10^\\var{ran - 2})  &= \\var{int*int} \\div \\var{int} \\times 10^{(\\var{ran - 4} - \\var{ran -2})} \\\\&= \\var{int} \\times 10^{-2} \\text{.}\\end{align} \\]

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$(\\var{int} \\times 10^\\var{ran - 3} ) \\times (\\var{int - 11} \\times 10^\\var{ran})  =$  [[0]]

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$(\\var{int*int} \\times 10^\\var{ran -4} ) \\div (\\var{int} \\times 10^\\var{ran - 2})  =$  [[0]]

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Add two numbers in standard form, then subtract two numbers in standard form.

", "licence": "Creative Commons Attribution 4.0 International"}, "type": "question", "advice": "

The easiest way to do this is to convert these numbers in standard form into decimals, do the calculation with decimal forms, then change them back into standard form.

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a)

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\\[\\begin{align} \\var{B[0]} \\times 10^3 + \\var{B[1]} \\times 10^4 &= \\var{B[0]*10^3} + \\var{B[1]*10^4} \\\\&= \\var{B[0]*10^3 + B[1]*10^4} \\\\&= \\var{(B[0]*10^3 + B[1]*10^4)/10^4} \\times 10^4\\end{align}\\]

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b)

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\\[\\begin{align} \\var{B[2]} \\times 10^3 - \\var{B[2] - 1.70} \\times 10^2 &= \\var{B[2]*10^3} - \\var{(B[2] - 1.70)*10^2} \\\\&= \\var{(B[2]*10^3) - ((B[2] - 1.70)*10^2)} \\\\&= \\var{(B[2]*10^3 - (B[2] - 1.70)*10^2)/10^3} \\times 10^3\\end{align}\\]

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Calculate the following and write the result in standard index form (for example, for $2.01\\times 10^5$ we would write 2.01*10^5 in the gap).

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$\\var{B[0]} \\times 10^3 + \\var{B[1]} \\times 10^4 =$  [[0]]

\n

\n

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$\\var{B[2]} \\times 10^3 - \\var{B[2] - 1.70} \\times 10^2 =$  [[0]]

\n

\n

\n

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+

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Questions on adding, subtracting, multiplying and dividing numbers in standard form.

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