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Substitute values into formulae for the area or volume of various geometric objects.
", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "Answer the following questions by substituting the correct values into the given equations.
", "advice": "When inserting numbers into your calculator, make sure that you place brackets correctly.
\nWe can see from the diagram that the radius of the frisbee is $\\var{mccall[2]}$ $\\mathrm{cm}$.
Replacing the letter $r$ in the formula for the area of a circle with $\\var{mccall[2]}$ gives,
\\begin{align}
\\mathrm{Area} &= \\pi r^2 \\\\
&= \\pi\\times(\\var{mccall[2]})^2 \\\\
&= \\var{dpformat((mccall[2])^2, 2)}\\pi\\, \\mathrm{cm}^2 \\\\
&= \\var{dpformat(pi *(mccall[2])^2, 2)}\\, \\mathrm{cm}^2 \\quad \\text{to 2 d.p.}
\\end{align}
We can see from the diagram that the triangle has two sides with lengths $\\var{length_cdp2}$ $\\mathrm{cm}$, $\\var{length_bdp2}$ $\\mathrm{cm}$ and an angle $\\var{c_thetadp2}\\mathrm{°}$ .
Replacing the letters $a$, $b$ and $C$ in the formula for the area of a triangle with $\\var{length_cdp2}$, $\\var{length_bdp2}$ and $\\var{c_thetadp2}$ respectively gives,
\\begin{align}
\\mathrm{Area} &= \\frac{1}{2}ab\\sin{C} \\\\
&= \\frac{1}{2} \\times \\var{length_cdp2} \\times \\var{length_bdp2} \\times \\sin(\\var{c_thetadp2}) \\\\
&= \\var{dpformat(0.5*(length_cdp2)*(length_bdp2)*sin(c_thetadp2* pi/180), 5)}\\, \\mathrm{cm}^2 \\\\
&= \\var{dpformat(0.5*(length_cdp2)*(length_bdp2)*sin(c_thetadp2 * pi/180), 2)}\\, \\mathrm{cm}^2 \\quad \\text{to 2 d.p.}
\\end{align}
We can see from the diagram that the radius of the cone is $\\var{r}$ $\\mathrm{cm}$ and the height is $\\var{h}$ $\\mathrm{cm}$.
Replacing the letters $r$ and $h$ in the formula for the volume of a cone with $\\var{r}$ $\\mathrm{cm}$ and $\\var{h}$ $\\mathrm{cm}$ respectively gives,
\\begin{align}
\\mathrm{Volume} &= \\frac{h}{3} \\pi r^2 \\\\
&= \\frac{(\\var{h})}{3} \\times \\pi \\times (\\var{r})^2 \\\\
&= \\var{dpformat((pi)*(h/3)*(r)^2 , 5)}\\, \\mathrm{cm}^3 \\\\
&=\\var{dpformat(h/3 * pi * (r)^2, 1)}\\, \\mathrm{cm}^3 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
\n
We can see from the diagram that the radius of the tennis ball is $\\var{mccall[1]}$ $\\mathrm{cm}$.
Replacing the letter $r$ in the formula for the volume of a sphere with $\\var{mccall[1]}$ gives,
\\begin{align}
\\mathrm{Volume} &= \\frac{4}{3} \\pi r^3 \\\\
&= \\frac{(4)}{(3)} \\times \\pi \\times (\\var{mccall[1]})^3 \\\\
&= \\var{dpformat((4/3)*pi*mccall[1]^3, 5)}\\, \\mathrm{cm}^3 \\\\
&= \\var{precround(((4/3)* pi) *(mccall[1])^3, 1)}\\, \\mathrm{cm}^3 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
We can see from the diagram that the trapezium has two parallel sides with length $\\var{trap_length_a}$ $\\mathrm{cm}$, $\\var{trap_length_b}$ $\\mathrm{cm}$ and height $\\var{trap_h}$ $\\mathrm{cm}$.
Replacing the letters $a$, $b$ and $h$ in the formula for the area of a trapezium with $\\var{trap_length_a}$, $\\var{trap_length_b}$ and $\\var{trap_h}$ respectively gives,
\\begin{align}
\\mathrm{Area} &= \\frac{1}{2} (a + b) h \\\\
&= \\frac{1}{2} \\times (\\var{trap_length_a} + \\var{trap_length_b}) \\times \\var{trap_h} \\\\
&= \\var{precround((0.5) (trap_length_a + trap_length_b) trap_h, 1)}\\, \\mathrm{cm}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
\\begin{align}
\\mathrm{Area} &= \\frac{1}{2} (a + b) h \\\\
&= \\frac{1}{2} \\times (\\var{trap_length_a} + \\var{trap_length_b}) \\times \\var{trap_h} \\\\
&= \\var{precround((0.5)(trap_length_a +trap_length_b) trap_h, 2)}\\, \\mathrm{cm}^2 \\\\
&= \\var{precround((0.5) (trap_length_a + trap_length_b) trap_h, 1)}\\, \\mathrm{cm}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
Rounded value for the length of c.
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\n\\[\\mathrm{Area} = \\pi r^2.\\]
\n\n$\\mathrm{Area}$ = [[0]] $\\mathrm{cm}^2$ Round your answer to 2 decimal places.
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\n{geogebra_applet('https://www.geogebra.org/m/jcUJu6F4',defs)}
\nAll lengths are in centimetres.
\n$\\mathrm{Area} =$ [[0]] $\\mathrm{cm}^2$ Round your answer to 2 decimal places.
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\n\\[\\mathrm{Volume} = \\frac{h}{3} \\pi r^2.\\]
\n\n$\\mathrm{Volume}$ = [[0]] $\\mathrm{cm}^3$ Round your answer to 1 decimal place.
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\n\\[\\mathrm{Volume}= \\frac{4}{3} \\pi r^3.\\]
\n\n$\\mathrm{Volume}$ = [[0]] $\\mathrm{cm}^3$ Round your answer to 1 decimal place.
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\n{geogebra_applet('https://www.geogebra.org/m/Gtjzajb6',trap_defs)}
\nAll lengths are given in metres.
\n$\\mathrm{Area}$ = [[0]] $\\mathrm{m}^2$ Round your answer to 1 decimal place.
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\nThe dimensions of the floor are $\\var{length}\\,\\mathrm{m} \\times \\var{width}\\,\\mathrm{m}$ and the room is $\\var{height}\\,\\mathrm{m}$ high.
\n{person['name']} want{verbs} to know how much paint to buy so {pronouns['they']} can paint all four walls and the ceiling {colour}.
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", "Underestimate and therefore we round each measurement down.
"], "showFeedbackIcon": true, "shuffleChoices": false, "displayColumns": "1", "variableReplacements": [], "marks": 0, "matrix": ["1", 0], "showCorrectAnswer": true, "maxMarks": 0, "type": "1_n_2"}], "showFeedbackIcon": true, "prompt": "Is it better to overestimate or underestimate in this situation?
\n[[0]]
", "marks": 0}, {"showCorrectAnswer": true, "scripts": {}, "variableReplacements": [], "type": "gapfill", "variableReplacementStrategy": "originalfirst", "showFeedbackIcon": true, "gaps": [{"correctAnswerFraction": false, "scripts": {}, "type": "numberentry", "variableReplacementStrategy": "originalfirst", "mustBeReducedPC": 0, "maxValue": "rall", "showFeedbackIcon": true, "minValue": "rall", "correctAnswerStyle": "plain", "allowFractions": false, "mustBeReduced": false, "notationStyles": ["plain", "en", "si-en"], "variableReplacements": [], "marks": 1, "showCorrectAnswer": true}], "stepsPenalty": 0, "prompt": "Rounding each measurement to the nearest metre, estimate the whole area to be painted {colour}.
\n[[0]] m2
\n", "steps": [{"scripts": {}, "variableReplacements": [], "type": "information", "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "showFeedbackIcon": true, "prompt": "
The room is {length}m long, {width}m wide, and {height}m high.
\nRound each measurement in the direction you decided on above.
", "marks": 0}, {"correctAnswerFraction": false, "scripts": {}, "type": "numberentry", "variableReplacementStrategy": "originalfirst", "allowFractions": false, "maxValue": "ceil(length)", "showFeedbackIcon": true, "prompt": "Round the length to the nearest metre.
", "minValue": "ceil(length)", "correctAnswerStyle": "plain", "mustBeReducedPC": 0, "mustBeReduced": false, "notationStyles": ["plain", "en", "si-en"], "variableReplacements": [], "marks": "0.1", "showCorrectAnswer": true}, {"correctAnswerFraction": false, "scripts": {}, "type": "numberentry", "variableReplacementStrategy": "originalfirst", "allowFractions": false, "maxValue": "ceil(width)", "showFeedbackIcon": true, "prompt": "Round the width to the nearest metre.
", "minValue": "ceil(width)", "correctAnswerStyle": "plain", "mustBeReducedPC": 0, "mustBeReduced": false, "notationStyles": ["plain", "en", "si-en"], "variableReplacements": [], "marks": "0.1", "showCorrectAnswer": true}, {"correctAnswerFraction": false, "scripts": {}, "type": "numberentry", "variableReplacementStrategy": "originalfirst", "allowFractions": false, "maxValue": "ceil(height)", "showFeedbackIcon": true, "prompt": "Round the height to the nearest metre.
", "minValue": "ceil(height)", "correctAnswerStyle": "plain", "mustBeReducedPC": 0, "mustBeReduced": false, "notationStyles": ["plain", "en", "si-en"], "variableReplacements": [], "marks": "0.1", "showCorrectAnswer": true}], "marks": 0}, {"scripts": {}, "variableReplacements": [], "type": "gapfill", "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "gaps": [{"correctAnswerFraction": false, "scripts": {}, "type": "numberentry", "variableReplacementStrategy": "originalfirst", "mustBeReducedPC": 0, "maxValue": "buckets", "showFeedbackIcon": true, "minValue": "buckets", "correctAnswerStyle": "plain", "allowFractions": false, "mustBeReduced": false, "notationStyles": ["plain", "en", "si-en"], "variableReplacements": [], "marks": 1, "showCorrectAnswer": true}], "showFeedbackIcon": true, "prompt": "One bucket of {colour} paint is enough to paint an area of 15m2. How many buckets should {person['name']} buy to ensure {pronouns['they']} {if(person['gender']='neutral','have','has')} enough paint?
\n[[0]]
", "marks": 0}], "ungrouped_variables": [], "rulesets": {}, "metadata": {"licence": "Creative Commons Attribution 4.0 International", "description": "Estimate the number of buckets of paint to buy, by rounding measurements of a room up to the nearest metre and estimating the total area.
"}, "preamble": {"css": "", "js": ""}, "advice": "It is much better to have spare paint than not to have enough of it. So it is better to overestimate the area.
\nTherefore, we round each measurement up.
\nWe round each of our measurements up to the nearest whole metre:
\nLength: $\\var{length}\\,\\mathrm{m} \\approx \\var{l}\\,\\mathrm{m}$.
\nWidth: $\\var{width}\\,\\mathrm{m} \\approx \\var{w}\\,\\mathrm{m}$.
\nHeight: $\\var{height}\\,\\mathrm{m} \\approx \\var{h}\\,\\mathrm{m}$.
\nThe total area consists of five areas: two walls of $\\var{l}\\,\\text{m} \\times \\var{h}\\,\\text{m}$ (length by height); two walls of $\\var{w}\\,\\text{m} \\times \\var{h}\\,\\text{m}$ (width by height); and a ceiling of $\\var{l}\\,\\text{m} \\times \\var{w}\\,\\text{m}$ (length by width).
\n\\[ \\begin{align}
\\var{l}\\,\\text{m} \\times \\var{h}\\,\\text{m} &= \\var{l*h}\\,\\text{m}^2
\\\\ \\var{w}\\,\\text{m} \\times \\var{h}\\,\\text{m} &= \\var{w*h}\\,\\text{m}^2
\\\\ \\var{l}\\,\\text{m} \\times \\var{w}\\,\\text{m} &= \\var{l*w}\\,\\text{m}^2
\\end{align}\\]
Therefore, the total area {person['name']} needs to paint is
\n\\[ \\var{2*l*h} + \\var{2*w*h} + \\var{l*w} \\,\\mathrm{m}^2 = \\var{rall}\\,\\mathrm{m}^2 \\text{.} \\]
\nThe exact number of buckets needed is
\n\\[\\var{rall}\\,\\text{m}^2 \\div 15\\,\\text{m}^2 = \\var{rall/15} \\text{.}\\]
\n{person['name']} can only buy a whole number of buckets, so {pronouns['they']} need{verbs} to decide between {buckets-1} and {buckets} paint buckets. As it is better to buy more paint than not buy enough, {pronouns['they']} should buy {buckets} buckets of {colour} paint.
"}, {"name": "Calculate the areas of polygons", "extensions": [], "custom_part_types": [], "resources": [["question-resources/trapezium.svg", "/srv/numbas/media/question-resources/trapezium.svg"], ["question-resources/trangle.svg", "/srv/numbas/media/question-resources/trangle.svg"], ["question-resources/parallelogram.svg", "/srv/numbas/media/question-resources/parallelogram.svg"], ["question-resources/Parallelogram_area_animated.gif", "/srv/numbas/media/question-resources/Parallelogram_area_animated.gif"], ["question-resources/rectangle_zISmvoz.svg", "/srv/numbas/media/question-resources/rectangle_zISmvoz.svg"], ["question-resources/hardertrapezium_8GqMwOo.svg", "/srv/numbas/media/question-resources/hardertrapezium_8GqMwOo.svg"], ["question-resources/Trap_advice.svg", "/srv/numbas/media/question-resources/Trap_advice.svg"], ["question-resources/Triangle_advice_lD6eKvD.svg", "/srv/numbas/media/question-resources/Triangle_advice_lD6eKvD.svg"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Vicky Hall", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/659/"}, {"name": "Aiden McCall", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1592/"}], "rulesets": {}, "functions": {}, "ungrouped_variables": [], "metadata": {"description": "This question tests the students ability to calculate the area of different 2D shapes given the units and measurements required. The formulae for the areas are available if required but students are encouraged to try to remember them themselves.
\nThe shapes are: a rectangle, a parallelogram, a right-angled triangle, and a trapezium.
\nAuthor of gif: Picknick
https://commons.wikimedia.org/wiki/File:Parallelogram_area_animated.gif
This file is licensed under the Creative Commons Attribution-Share Alike 4.0 International license.
a)
\nThe area of a rectangle is calculated using the formula
\n\\[\\mathrm{Area} = \\mathrm{base} \\times \\mathrm{height}\\text{.}\\]
\nWe have a base of $\\var{w0}$m and a height $\\var{h0}$m, therefore
\n\\begin{align}
\\mathrm{Area} &= \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\var{w0} \\times \\var{h0} \\\\ &= \\var{w0*h0} \\\\
&= \\var{dpformat(w0*h0,1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
\\begin{align}
\\mathrm{Area} &= \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\var{w0} \\times \\var{h0} \\\\
&= \\var{dpformat(w0*h0,1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
b)
\nThe parallelogram is just a slanted rectangle:
\n\n\nTherefore, the area of a parallelogram is calculated using the formula
\n\\[\\mathrm{Area} = \\mathrm{base} \\times \\mathrm{height}.\\]
\nWe have a base $\\var{w1}$m and perpendicular height $\\var{h1}$m.
\n\\begin{align}
\\mathrm{Area} &= \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\var{w1} \\times \\var{h1} \\\\ &= \\var{{w1}{h1}}\\, \\mathrm{m}^2 \\\\
&= \\var{dpformat({w1}{h1},1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
\\begin{align}
\\mathrm{Area} &= \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\var{w1} \\times \\var{h1} \\\\
&= \\var{dpformat({w1}{h1},1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
The area of a triangle is calculated using the formula
\n\\[\\mathrm{Area} = \\frac{\\mathrm{base} \\times \\mathrm{height}}{2}.\\]
\nNote that the triangle is half of a rectangle:
\n\nOur triangle has a base $\\var{w2}$m and a height $\\var{h2}$m, therefore
\n\\begin{align} \\mathrm{Area} &= \\frac{1}{2} \\times \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\frac{1}{2} \\times \\var{w2} \\times \\var{h2} \\\\
&= \\var{0.5*w2*h2}\\, \\mathrm{m}^2 \\\\
&= \\var{dpformat(0.5*w2*h2, 1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
\\begin{align} \\mathrm{Area} &= \\frac{1}{2} \\times \\mathrm{base} \\times \\mathrm{height} \\\\
&= \\frac{1}{2} \\times \\var{w2} \\times \\var{h2} \\\\
&= \\var{dpformat(0.5*w2*h2, 1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.} \\\\
\\end{align}
d)
\n\nA trapezium can be interpreted as half of a parallelogram, this is shown below:
\n\nAs we only want the area of one half of this shape, the area is half of
\n\\[\\mathrm{area} = (a+b) \\times \\mathrm{height}\\text{,}\\]
\nwith ${a} = \\var{w5a}$m, ${b} = \\var{w5b}$m, and height $\\var{h5}$m.
\n\\begin{align}
\\mathrm{Area} &= \\frac{(a+b)}{2} \\times \\mathrm{height} \\\\
&= \\frac{(\\var{w5a}+\\var{w5b})}{2} \\times \\var{h5} \\\\
&= \\var{(w5a+w5b)*0.5} \\times \\var{h5} \\\\
&= \\var{(w5a+w5b)*(h5)/2}\\, \\mathrm{m}^2 \\\\
&= \\var{dpformat((w5a+w5b)*(h5)/2, 1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.}
\\end{align}
\\begin{align}
\\mathrm{Area} &= \\frac{(a+b)}{2} \\times \\mathrm{height} \\\\
&= \\frac{(\\var{w5a}+\\var{w5b})}{2} \\times \\var{h5} \\\\
&= \\var{(w5a+w5b)*0.5} \\times \\var{h5} \\\\
&= \\var{dpformat((w5a+w5b)*(h5)/2, 1)}\\, \\mathrm{m}^2 \\quad \\text{to 1 d.p.}
\\end{align}
Calculate the area of the following shapes.
", "preamble": {"css": "", "js": ""}, "tags": ["area", "Area", "area of a parallelogram", "area of a rectangle", "area of a right-angled triangle", "area of a trapezium", "parallelogram", "Rectangle", "rectangle", "right - angled triangle", "shapes", "taxonomy", "trapezium"], "parts": [{"variableReplacementStrategy": "originalfirst", "prompt": "\nThe area of the rectangle is [[0]] $\\mathrm{m^2}$. Round your answer to 1 decimal place.
", "gaps": [{"variableReplacementStrategy": "originalfirst", "showPrecisionHint": false, "variableReplacements": [], "precision": "1", "correctAnswerStyle": "plain", "strictPrecision": false, "type": "numberentry", "precisionMessage": "You have not given your answer to the correct precision.", "correctAnswerFraction": false, "maxValue": "{h0}{w0}", "allowFractions": false, "notationStyles": ["plain", "en", "si-en"], "precisionType": "dp", "minValue": "{h0}{w0}", "mustBeReduced": false, "showCorrectAnswer": true, "showFeedbackIcon": true, "mustBeReducedPC": 0, "precisionPartialCredit": 0, "marks": "2", "scripts": {}}], "stepsPenalty": "1", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "gapfill", "marks": 0, "steps": [{"variableReplacementStrategy": "originalfirst", "prompt": "The formula for the area of a rectangle is:
\n\\[\\mathrm{Area} = \\mathrm{base} \\times \\mathrm{height}.\\]
", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "information", "marks": 0, "showCorrectAnswer": true}], "showCorrectAnswer": true}, {"variableReplacementStrategy": "originalfirst", "prompt": "\nThe area of the parallelogram is [[0]] $\\mathrm{m^2}$. Round your answer to 1 decimal place.
", "gaps": [{"variableReplacementStrategy": "originalfirst", "showPrecisionHint": false, "variableReplacements": [], "precision": "1", "correctAnswerStyle": "plain", "strictPrecision": false, "type": "numberentry", "precisionMessage": "You have not given your answer to the correct precision.", "correctAnswerFraction": false, "maxValue": "{h1}*{w1} + 0.01", "allowFractions": false, "notationStyles": ["plain", "en", "si-en"], "precisionType": "dp", "minValue": "{h1}*{w1} - 0.01", "mustBeReduced": false, "showCorrectAnswer": true, "showFeedbackIcon": true, "mustBeReducedPC": 0, "precisionPartialCredit": 0, "marks": "2", "scripts": {}}], "stepsPenalty": "1", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "gapfill", "marks": 0, "steps": [{"variableReplacementStrategy": "originalfirst", "prompt": "The formula for the area of a parallelogram is:
\n\\[\\mathrm{Area} = \\mathrm{base} \\times \\mathrm{height}.\\]
", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "information", "marks": 0, "showCorrectAnswer": true}], "showCorrectAnswer": true}, {"variableReplacementStrategy": "originalfirst", "prompt": "\nThe area of the triangle is [[0]] $\\mathrm{m^2}$ Round your answer to 1 decimal place.
", "gaps": [{"variableReplacementStrategy": "originalfirst", "showPrecisionHint": false, "variableReplacements": [], "precision": "1", "correctAnswerStyle": "plain", "strictPrecision": false, "type": "numberentry", "precisionMessage": "You have not given your answer to the correct precision.", "correctAnswerFraction": false, "maxValue": "{w2}{h2}*0.5 + 0.01", "allowFractions": false, "notationStyles": ["plain", "en", "si-en"], "precisionType": "dp", "minValue": "{w2}{h2}*0.5 - 0.01", "mustBeReduced": false, "showCorrectAnswer": true, "showFeedbackIcon": true, "mustBeReducedPC": 0, "precisionPartialCredit": 0, "marks": "2", "scripts": {}}], "stepsPenalty": "1", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "gapfill", "marks": 0, "steps": [{"variableReplacementStrategy": "originalfirst", "prompt": "The formula for the area of a triangle is:
\n\\[\\mathrm{Area} = \\frac{\\mathrm{base} \\times \\mathrm{height}}{2}.\\]
", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "information", "marks": 0, "showCorrectAnswer": true}], "showCorrectAnswer": true}, {"variableReplacementStrategy": "originalfirst", "prompt": "\nThe area of the trapezium is [[0]] $\\mathrm{m^2}$. Round your answer to 1 decimal place.
", "gaps": [{"variableReplacementStrategy": "originalfirst", "showPrecisionHint": false, "variableReplacements": [], "precision": "1", "correctAnswerStyle": "plain", "strictPrecision": false, "type": "numberentry", "precisionMessage": "You have not given your answer to the correct precision.", "correctAnswerFraction": false, "maxValue": "0.5{w5a+w5b}{h5} + 0.01", "allowFractions": false, "notationStyles": ["plain", "en", "si-en"], "precisionType": "dp", "minValue": "0.5{w5a+w5b}{h5} - 0.01", "mustBeReduced": false, "showCorrectAnswer": true, "showFeedbackIcon": true, "mustBeReducedPC": 0, "precisionPartialCredit": 0, "marks": "2", "scripts": {}}], "stepsPenalty": "1", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "gapfill", "marks": 0, "steps": [{"variableReplacementStrategy": "originalfirst", "prompt": "The formula for the area of a trapezium is:
\n\\[\\mathrm{Area} = \\frac{(a+b)}{2}\\times \\mathrm{height}.\\]
", "variableReplacements": [], "showFeedbackIcon": true, "scripts": {}, "type": "information", "marks": 0, "showCorrectAnswer": true}], "showCorrectAnswer": true}], "variables": {"h2": {"name": "h2", "description": "Height of the triangle.
", "templateType": "anything", "group": "Triangle", "definition": "random(1..4.5#0.1)"}, "wh22dp": {"name": "wh22dp", "description": "The Area of a triangle using the two terms, w2 and h2 to one decimal place, such that a condition can be satisfied.
", "templateType": "anything", "group": "Triangle", "definition": "precround(0.5*w2*h2, 1)"}, "wabh5": {"name": "wabh5", "description": "The Area of a trapezium using the three terms, w5a, w5b and h5, such that a condition can be satisfied.
", "templateType": "anything", "group": "'Harder' trapezium", "definition": "precround((w5a+w5b)*(h5)/2, 5)"}, "w5b": {"name": "w5b", "description": "The bottom parallel side in the trapezium.
", "templateType": "anything", "group": "'Harder' trapezium", "definition": "random(7.5..10#0.1)"}, "wh11": {"name": "wh11", "description": "The product of the two terms, w1 and h1, such that a condition can be satisfied.
", "templateType": "anything", "group": "Parallelogram", "definition": "precround(w1*h1,3)"}, "w1": {"name": "w1", "description": "The width of the parallelogram.
", "templateType": "anything", "group": "Parallelogram", "definition": "random(5..10#0.1)"}, "wabh5dp": {"name": "wabh5dp", "description": "The Area of a trapezium using the three terms, w5a, w5b and h5 to one decimal place, such that a condition can be satisfied.
", "templateType": "anything", "group": "'Harder' trapezium", "definition": "precround((w5a+w5b)*(h5)/2, 1)"}, "h1": {"name": "h1", "description": "The height of the parallelogram
", "templateType": "anything", "group": "Parallelogram", "definition": "random(1..4.5#0.1)"}, "w0": {"name": "w0", "description": "Width of the rectangle.
", "templateType": "anything", "group": "Rectangle", "definition": "random(5..10#0.1)"}, "wh22": {"name": "wh22", "description": "The Area of a triangle using the two terms, w2 and h2, such that a condition can be satisfied.
", "templateType": "anything", "group": "Triangle", "definition": "precround(0.5*w2*h2,4)"}, "w2": {"name": "w2", "description": "Base of the triangle.
", "templateType": "anything", "group": "Triangle", "definition": "random(5..10#0.1)"}, "h5": {"name": "h5", "description": "Height of the trapezium.
", "templateType": "anything", "group": "'Harder' trapezium", "definition": "random(2..5#0.1)"}, "wh00dp": {"name": "wh00dp", "description": "The product of the two terms, w0 and h0, to one decimal place, such that a condition can be satisfied.
", "templateType": "anything", "group": "Rectangle", "definition": "precround(w0*h0,1)"}, "wh00": {"name": "wh00", "description": "The product of the two terms, w0 and h0, such that a condition can be satisfied.
", "templateType": "anything", "group": "Rectangle", "definition": "precround(w0*h0,3)"}, "h0": {"name": "h0", "description": "Height of the rectangle.
", "templateType": "anything", "group": "Rectangle", "definition": "random(1..5#0.1)"}, "w5a": {"name": "w5a", "description": "The top parallel side in the trapezium.
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