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Simple Linear Equations, substitution

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Solve a simple linear equation algebraically. The unknown appears on both sides of the equation.

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$\\var{d}x-\\var{f}=\\var{g}x+\\var{h}$

\n

What is the value of $x$?

\n

$x = $ [[0]]

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We are asked to solve the equation

\n

\\[ \\var{d}x-\\var{f}=\\var{g}x+\\var{h} \\]

\n

In this equation, there are $x$ terms and constant terms on both sides of the equals sign.

\n

To solve this equation, we must rearrange it to get $x$ on its own.

\n

\\begin{align}
\\var{d}x-\\var{f} &= \\var{g}x+\\var{h} \\\\[0.5em]
\\var{d}x-\\var{g}x &= \\var{h}+\\var{f} & \\text{Move } x \\text{ terms to the left, and constant terms to the right.}\\\\[0.5em]
\\simplify{{d-g}*x} &= {\\var{h+f}} & \\text{Collect like terms together.}\\\\[0.5em]
x &=\\frac{\\var{h+f}}{\\var{d-g}} & \\text{Divide both sides by } \\var{d-g} \\text{.} \\\\[0.5em]
x &= \\simplify{{h+f}/{d-g}}
\\end{align}

", "statement": "", "functions": {}, "type": "question"}, {"name": "Solve a linear equation $ax+b = c$", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "contributors": [{"name": "Christian Lawson-Perfect", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/7/"}, {"name": "Lauren Richards", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1589/"}], "metadata": {"description": "

Solve a linear equation of the form $ax+b = c$, where $a$, $b$ and $c$ are integers.

\n

The answer is always an integer.

", "licence": "Creative Commons Attribution 4.0 International"}, "ungrouped_variables": [], "type": "question", "rulesets": {}, "advice": "

We need to solve the equation

\n

\\[ \\var{a}x+\\var{b}=\\var{c} \\]

\n

To solve this equation, we must rearrange the equation to put $x$ on its own.

\n

To do this, we should subtract $\\var{b}$ from both sides and then divide through by $\\var{a}$ to get the value for $x$.

\n

\\begin{align}
\\var{a}x+\\var{b}&=\\var{c} \\\\[0.5em]
\\var{a}x&=\\var{c}-\\var{b} & \\text{Subtract } \\var{b} \\text{ from both sides} \\\\[0.5em]
\\var{a}x&=\\var{c-b} \\\\[0.5em]
x&=\\frac{\\var{c-b}}{\\var{a}} & \\text{Divide both sides by } \\var{a} \\\\[0.5em]
x&=\\simplify{{c-b}/{a}}
\\end{align}

\n

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$\\var{a}x+\\var{b}=\\var{c}$

\n

What is the value of $x$?

\n

$x = $ [[0]]

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Substitute given values into formulas.

", "licence": "Creative Commons Attribution 4.0 International"}, "ungrouped_variables": ["r", "x1", "n", "x2", "const", "sales"], "type": "question", "advice": "

When inserting numbers into your calculator make sure you place brackets correctly.

\n

a) 

\n

As $x = \\var{n+2}$,

\n

substitute $\\var{n+2}$ into $\\var{x2}x^2 + \\var{x1}x + \\var{const}$.

\n

\\begin{align}
\\var{x2}x^2 + \\var{x1}x + \\var{const} &= \\var{x2} (\\var{n+2})^2 + \\var{x1}(\\var{n+2}) + \\var{const} \\\\
&=  \\simplify{{x2} ({n+2})^2 + {x1}({n+2}) + {const}}\\,.
\\end{align}

\n

b)

\n

As $y =  \\var{n}$,

\n

substitute $\\var{n}$ into $\\var{n+1}y^2-\\var{x2}y$.

\n

\\begin{align}
\\var{n+1}y^2-\\var{x2}y &=  \\var{n+1}(\\var{n})^2-\\var{x2}(\\var{n}) \\\\
&=  \\simplify{{n+1}({n})^2-{x2}({n})}\\,.
\\end{align}

\n

c)

\n

As we are given a temperature in degrees Celcius, $T_C = \\var{T_C}°C.$

\n

Substituting $T_C$ into $T_C = 1.8\\,T_C + 32$.

\n

\\begin{align}
T_F &=1.8\\, T_C+32 \\\\
&=1.8 (\\var{T_C}) + 32 \\\\
&= \\var{dpformat(1.8 {T_C} +32, 1)}\\,°F\\,.
\\end{align}

\n

\n

\n

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Substitute the given values in the equations below.

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A curve is defined by a function $y=\\simplify{{x2}x^2 + {x1}x + {const}}$.

\n

What is the $y$ coordinate value of the point on the curve at $x=\\var{n+2}$?

\n

$y =$ [[0]]

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{name[n]} sells luxury yachts.

\n

The predicted sales of the luxury yachts are defined by

\n

\\[S=\\simplify{{n+1}y^2-{x2}y},\\]

\n

where
$S$ is the number of sales predicted this year;
$y$ is the number of luxury yachts sold in the previous year.

\n

{pronoun} sold {n} yachts in the previous year.

\n

Calculate $S$, the number of sales predicted this year.

\n

$S =$ [[0]]

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You can convert temperatures from degrees celsius to degrees fahrenheit by using the formula

\n

\\[T_F=1.8\\, T_C+32,\\]

\n

where
$T_F$ = Temperature in $°F$
$T_C$ = Temperature in $°C$.

\n

Convert $\\var{T_C}°C$ into degrees fahrenheit.

\n

$T_F =$ [[0]] $°F$  

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Defines the pronoun in the question.

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Creates a random integer value for the temperature in degrees celcius.

", "definition": "random(5..30#1)", "group": "Temperature conversion", "name": "T_C", "templateType": "anything"}, "name": {"description": "

List of names to randomise. Can change to any name inserted

", "definition": "[\"Andrew\",\"Susan\",\"Tom\",\"Geraldine\",\"Joshua\",\"Chantel\"]", "group": "Name variables", "name": "name", "templateType": "anything"}, "n": {"description": "

n is a random number between 0 and 4 that picks a name from {name} and then picks the next in the list for the other name such that there is always a male and a female in the question. 

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The constant coefficient

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Creates a value for Temperature in fahrenheit.

", "definition": "T_C*1.8+32", "group": "Temperature conversion", "name": "T_F", "templateType": "anything"}, "r": {"description": "

A random variable which will be inputted by the student.

", "definition": "random(1..50#0.1)", "group": "Ungrouped variables", "name": "r", "templateType": "anything"}, "x2": {"description": "

The x^2 coefficient

", "definition": "random(1..(n+1)*n)", "group": "Ungrouped variables", "name": "x2", "templateType": "anything"}, "name2": {"description": "

List of names to randomise. Can change to any name inserted

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The x coefficient

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Part 1:

\n

$x$:

\n

$\\frac{(\\var{numh[0]}-\\var{num1p[1]})}{(\\var{num1p[0]}-\\var{num1p[2]})} = \\var{ans11}$

\n

Part 2:

\n

$x$:

\n

$\\frac{((\\var{num1p[7]} \\times \\var{num1p[6]})-(\\var{num1p[4]} \\times \\var{num1n[2]})}{((\\var{num1p[1]} \\times \\var{num1p[5]})-(\\var{num1p[7]} \\times \\var{num1n[7]})} = \\var{ans21}$

\n

Part 3:

\n

$x$:

\n

$\\frac{((\\var{num3p[4]} \\times \\var{num3p[5]})+\\var{num3p[6]}+(\\var{num3n[4]} \\times \\var{num3n[5]})-\\var{num3p[0]}-(\\var{num3p[1]} \\times \\var{num3n[0]})-(\\var{num3n[1]} \\times \\var{num3n[2]}))}  {((\\var{num3p[1]} \\times \\var{num3p[2]})+(\\var{num3n[1]} \\times \\var{num3p[3]})-(\\var{num3p[4]} \\times \\var{num3n[3]})-(\\var{num3n[4]} \\times \\var{num3p[7]}))} = \\var{ans31}$

\n

Part 4:

\n

$x$:

\n

$\\frac{(\\var{nega[3]}-\\frac{\\var{nega[1]}}{\\var{posa[1]}}+\\frac{\\var{posa[5]}}{\\var{posa[3]}}-\\frac{\\var{nega[2]}}{\\var{posa[6]}})}  {(\\frac{\\var{posa[2]}}{\\var{posa[1]}}-\\frac{\\var{posa[4]}}{\\var{posa[3]}}+\\frac{\\var{posa[7]}}{\\var{posa[6]}})} = \\var{ans41}$

\n

Part 5:

\n

$x$:

\n

$\\frac{((\\var{posb[3]} \\times \\var{nega[4]}) - (\\var{posb[1]} \\times \\var{posb[5]}))}{((\\var{posb[1]} \\times \\var{posb[4]}) - (\\var{posb[3]} \\times \\var{posb[2]}))} = \\var{ans51}$

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$\\var{num1p[0]}x + \\var{num1p[1]} = \\var{num1p[2]}x + \\var{numh[0]}$

\n

$x =$  [[0]]

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$\\var{num1p[4]}(\\var{num1p[5]}  \\var{num1n[2]}x) = \\var{num1p[7]}(\\var{num1p[6]}  \\var{num1n[7]}x)$

\n

$x =$  [[0]]

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$\\var{num3p[0]} + \\var{num3p[1]}(\\var{num3p[2]}x \\var{num3n[0]})\\var{num3n[1]}(\\var{num3p[3]}x \\var{num3n[2]}) = \\var{num3p[4]}(\\var{num3p[5]}  \\var{num3n[3]}x) + \\var{num3p[6]} \\var{num3n[4]}(\\var{num3p[7]}x \\var{num3n[5]})$

\n

$x =$  [[0]]

\n

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$\\frac{1}{\\var{posa[1]}}(\\var{posa[2]}x \\var{nega[1]})-\\frac{1}{\\var{posa[3]}}(\\var{posa[4]}x +\\var{posa[5]})+\\frac{1}{\\var{posa[6]}}(\\var{posa[7]}x \\var{nega[2]}) = \\var{nega[3]}$

\n

$x =$  [[0]]

", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "steps": [{"prompt": "

Get a common denominator like in question 1. The multiply both sides of the equation by that common denominator to get rid of the fractions.

", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "information"}], "gaps": [{"precisionType": "dp", "precisionMessage": "You have not given your answer to the correct precision.", "allowFractions": false, "variableReplacements": [], "maxValue": "{ans41}+0.5", "strictPrecision": false, "minValue": "{ans41}-0.5", "variableReplacementStrategy": "originalfirst", "precisionPartialCredit": 0, "correctAnswerFraction": false, "showCorrectAnswer": true, "precision": "2", "scripts": {}, "marks": 1, "type": "numberentry", "showPrecisionHint": false}], "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "gapfill"}, {"prompt": "

$\\frac{\\var{posb[1]}}{\\var{posb[2]}x\\var{neg[4]}}= \\frac{\\var{posb[3]}}{\\var{posb[4]}x+\\var{posb[5]}}$

\n

$x =$  [[0]]

", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "gaps": [{"precisionType": "dp", "precisionMessage": "You have not given your answer to the correct precision.", "allowFractions": false, "variableReplacements": [], "maxValue": "{ans51}+0.5", "strictPrecision": false, "minValue": "{ans51}-0.5", "variableReplacementStrategy": "originalfirst", "precisionPartialCredit": 0, "correctAnswerFraction": false, "showCorrectAnswer": true, "precision": "2", "scripts": {}, "marks": 1, "type": "numberentry", "showPrecisionHint": false}], "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "gapfill"}], "statement": "

Solve for $x$ in the following, to 2 decimal places:

\n

Watch the video below for help with the questions:

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Solving Equations

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Simple Linear Equations involving basic transposition

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rebelmaths

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