Clodagh's copy of Julie's copy of Calculate probabilities from normal distribution,

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Question 1

The electricity consumption, $X$ , of a frozen foods warehouse each week in the summer months is normally distributed with mean 850k Wh and standard deviation 70k Wh.

Find the probability that in a particular week the electricity consumption is less than 800 k Wh:

Probability = ?Expected answer:(to 2 decimal places)

Find the probability that in a particular week the electricity consumption is greater than 920 k Wh:

Probability = ?Expected answer:(to 2 decimal places)

Score: 0/2

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Advice

1. Converting to $\operatorname{N}(0,1)$

$\simplify[all,!collectNumbers]{P(X < {lower}) = P(Z < ({lower} -{m}) / {s}) =1 -P(Z < {m-lower}/{s})} = 1-P(z<\var{zlower})=1 -\var{p} = \var{prob1}$ to 2 decimal places.

2. Converting to $\operatorname{N}(0,1)$

$\simplify[all,!collectNumbers]{P(X > {upper}) = P(Z > ({upper} -{m}) / {s}) = 1 -P(Z < {upper-m}/{s})} = 1-P(z<\var{zupper})=1-\var{p1} = \var{prob2}$ to 2 decimal places.

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Clodagh's copy of Julie's copy of Calculate probabilities from normal distribution,

Advice