Imperial to metric: feet and inches to centimetres

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Question 1

Complete the following conversion from imperial to metric units.

A patient reports their height to be $\var{hft}' \text{ (feet) and }\var{hin}'' \text{(inches)}$ . Find their height in metres correct to two decimal places by using that $1 \text{ foot} = 12 \text { inches}$ and $1 \text{ inch} = 2.54 \text{ cm}$ .

Height $=$ Expected answer: m (2 dec. pl.)

$1 \text{ foot} = 12 \text{ inches}$ , and so $\var{hft} \text{ feet} = \var{hft} \times 12 \text{ inches} = \var{ft2in} \text{ inches}$ .

Add on the additional $\var{hin} \text{ inches}$ , and the patient's height in inches is $\var{totin} \text{ inches}$ .

Given $1 \text{ inch} = 2.54 \text{ cm}$ , we must have $\var{totin} \text{ inches} = \var{totin} \times 2.54 \text{ cm}$ .

We could use the calculator for this multiplication but we should also be able to do it without one.

Without a calculator we determine $\var{totin}\times 254$ (which is $\var{precround(hcm*100,0)}$ ) and then move the decimal place so we have two decimal places again (that is $\var{hcm} \text{ cm}$ ).

Then converting to metres, by moving the decimal place to the left twice, we get

$\text{Height} = \var{hm} \text{ m}$ .

Now we have the height in metres, we can round to two decimal places (that is, $\var{twodec}0$ m ).

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Imperial to metric: feet and inches to centimetres

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