Question 1 In the following question find the (x,y) coordinates of the single stationary point (a,b)∈D of the continuous function f:D→R: f(x,y)=1−9e−(x−1)2−(y+6)2 where D={(x,y):(x−1)2+(y+6)2}≤2 That is, D is a disk of radius √2 and centre (1,−6). Input both cooordinates as fractions or integers and not decimals. x–coordinate, a= Expected answer: y–coordinate, b= Expected answer: Input the value of f(x,y) at (a,b): f(a,b)= Expected answer: If you want some help, click on Show steps. You will not lose any marks if you do so. The (x,y) coordinates of the stationary point of a function of 2 variables f(x,y) are given by solvingthe following 2 equations for x and y ∂f∂x=0∂f∂y=0 In this case you get two equations to solve for x and y Answer saved Not marked Feedback for . Show feedback.The feedback has changed.This feedback is based on your last submitted answer. Save your changed answer to get updated feedback. What do you want to do next? ⤺ Go back to the previous part There's nothing more to do from here. Show stepsHide steps(Your score will not be affected.) Save answer Score: 0/5 Feedback for . Hide feedback.The feedback has changed.This feedback is based on your last submitted answer. Save your changed answer to get updated feedback. Or, you could: ⤺ Go back to the previous part There's nothing more to do from here. Advice The (x,y) coordinates of the stationary point of a function of 2 variables f(x,y) are given by solvingthe following 2 equations for x and y ∂f∂x=0∂f∂y=0 In this case you get two equations to solve for x and y 18(x−1)e−(x−1)2−(y+6)2=018(y+6)e−(x−1)2−(y+6)2=0We can cancel off the term e−(x−1)2−(y+6)2 in both equations as e−(x−1)2−(y+6)2≠0,∀x,y. On solving these we get x=1,y=−6 So the stationary point is (1,−6)∈D. On substituting these values into f(x,y) we get: f(1,−6)=1−9=−8 Score: 0/5 Total 0/5 Move to the next questionTry another question like this oneReveal answers