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General rules for partial fractions:

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$\\frac{P(x)}{(ax+b)(cx+d)}=\\frac{A}{ax+b}+\\frac{B}{cx+d}$
$\\frac{P(x)}{(ax+b)^2}=\\frac{A}{ax+b}+\\frac{B}{(ax+b)^2}$
$\\frac{P(x)}{(ax^2+bx+c)(dx+e)}=\\frac{Ax+B}{ax^2+bx+c}+\\frac{C}{dx+e}$

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Find the partial fraction of:

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$\\frac{3x + 14}{x^2 + 8x + 16}$

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$ = [[0]]/$(x+4)$ + [[1]]/$(x+4)^2$

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