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Find the equation from the image of graph
", "licence": "None specified"}, "statement": "You can zoom and pan this image
\n{app}
To find the gradient
\nFirstly draw a right angled 'step' from left to right. This triangle can be anywhere, but it is more helpful for it to have corners on the vertices (whole number points) of the graph and it is easier to calculate with postive numbers.
\n{app_advice}
\nBefore we start to calculate, notice that the line is {uod}, so the gradient will be {pon} and the line is {sos}, so the absolute value of the number will be {mol}.
Now find the coordinates of the places your triangle meets the line
$(x_1,y_1)=(\\var{ax},\\var{ay})$ and $(x_2,y_2)=(\\var{bx},\\var{by})$
\nWe need to compare the 'rise on the y-axis' to the 'run across the x-axis', we can say that:
\n$\\text{gradient} = \\frac{\\text{rise}}{\\text{run}}$
\nThis is equivalent to using the formula:
$ m = \\frac{y_2 - y_1}{x_2 - x_1} $
and substitute the coordinates of the vertices of the triangle:
$\\begin{split} &\\, m = \\frac{\\var{by} - \\var{ay}}{\\var{bx} - \\var{ax}} \\\\
&\\, = \\frac{\\var{by-ay}}{\\var{bx-ax}} \\\\
&\\, = \\var[fractionNumbers]{m} \\\\
\\end{split} $
\n
To complete the equation
\nYou can either read the intercept from the graph (if it is obvious where the line cuts the y-axis) or you can calculate it.
\nWe know there gradient so we can write $y=\\var{m}x+c$ and rearrange to give us:
\n$c = \\simplify[all]{y - {m}x}$
Then subsitute the value of $x$ and $y$ from any point on the line, let's use $(\\var{ax},\\var{ay})$ to give
$c = \\var{ay} \\simplify[all]{- {m}} \\times \\var{ax}$
\n$c = \\var{c}$
\nSo the final equation is
\n$y = \\simplify[collectNumbers, zeroterm,unitfactor]{{m}x +{c}}$
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