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Rearraning the constant acceleration equation $v^2=u^2+2as$ to make $u$ the subject.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Rearrange the constant acceleration equation \\[ v^2=u^2+2as \\] to make $u$ the subject.
", "advice": "If we want to make $u$ the subject of the equation $v^2=u^2+2as$, this can be broken down into steps.
\nFirstly, we want to subtract $2as$ from both sides:
\n\\[ \\begin{split} &\\,v^2=u^2+2as \\\\\\\\ \\implies &\\,v^2-2as=u^2 \\,.\\end{split} \\]
\nNow the right-hand side of the equation is only $u^2$, so by taking the square root of both sides we can obtain an expression for $u$:
\n\\[ \\begin{split}v^2-2as=u^2 \\\\\\\\ \\implies \\sqrt{v^2-2as} &\\,=u \\,.\\end{split} \\]
\nTherefore, the equation with $u$ as the subject is \\[ u=\\sqrt{v^2-2as} \\,.\\]
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