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More difficult trigonometric equations with radians

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Solve the following equations in radians, for $\\theta$ in the range $0\\leq\\theta\\leq\\pi$:

\n

\\[\\var{b}\\cos(3\\theta+\\var{d})=\\var{c}\\]

\n

Give your answers for parts (b) (c) and (d) correct to 2 decimal places in ascending order.

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$\\cos(3\\theta+\\var{d})=$ [[0]]

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$3\\theta+\\var{d}=$ [[0]] , [[1]], [[2]] or [[3]]

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$3\\theta=$ [[0]] , [[1]], [[2]] or [[3]]

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$\\theta=$ [[0]] , [[1]] or [[2]]

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(Discard any solutions not in range.)

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