// Numbas version: exam_results_page_options {"name": "JSXGraph: interactive 2D optimisation", "extensions": ["jsxgraph"], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "JSXGraph: interactive 2D optimisation", "tags": [], "metadata": {"description": "

A 2D linear programming problem: optimise the profit from producing two different kinds of product, which both use the same limited resources.

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A JSXGraph diagram illustrates the problem and can be used to find an answer.

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

A factory produces two items, {prod_1_name} and {prod_2_name}.

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They both use {resource_1_name} and {resource_2_name}.

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You have {max_resource_1} {resource_1_unit} {resource_1_name} and {max_resource_2} {resource_2_unit} {resource_2_name}.

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Each {prod_1_name} uses {resource_1_per_prod_1} {resource_1_unit} {resource_1_name} and {resource_2_per_prod_1} {resource_2_unit} {resource_2_name}, and can be sold for {currency(prod_1_price,\"£\",\"p\")}.

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Each {prod_2_name} uses {resource_1_per_prod_2} {resource_1_unit} {resource_1_name} and {resource_2_per_prod_2} {resource_2_unit} {resource_2_name}, and can be sold for {currency(prod_2_price,\"£\",\"p\")}.

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The graph below shows these constraints: the horizontal axis corresponds to the number of {prod_1_name} produced, and the vertical axis corresponds to the number of {prod_2_name} produced.

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The solid lines show the constraints corresponding to the amounts of {resource_1_name} and {resource_2_name} available, and the dashed line represents revenue.

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{diagram}

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},function() {\"\"\"+\"\"\" return oa.Y() - {prod_1_price/prod_2_price}; }) <>;\n objective = line(oa,ob) <>;\n\"\"\")", "description": "", "templateType": "anything", "can_override": false}, "prod_1_max_production": {"name": "prod_1_max_production", "group": "Setup", "definition": "min(max_resource_1/resource_1_per_prod_1, max_resource_2/resource_2_per_prod_1)", "description": "", "templateType": "anything", "can_override": false}, "prod_2_max_production": {"name": "prod_2_max_production", "group": "Setup", "definition": "min(max_resource_1/resource_1_per_prod_2, max_resource_2/resource_2_per_prod_2)", "description": "", "templateType": "anything", "can_override": false}, "points_to_consider": {"name": "points_to_consider", "group": "Marking", "definition": "[\n [floor(prod_1_max_production),0],\n [0,floor(prod_2_max_production)]\n] + let([ix,iy],intersection,\n [[floor(ix),floor(iy)], [floor(ix),ceil(iy)], [ceil(ix),floor(iy)]]\n)", "description": "", "templateType": "anything", "can_override": false}, "intersection": {"name": "intersection", "group": "Marking", "definition": "let(\n m, matrix([resource_1_per_prod_1, resource_1_per_prod_2], [resource_2_per_prod_1, resource_2_per_prod_2]),\n d, det(m),\n im, 1/d * matrix([resource_2_per_prod_2, -resource_1_per_prod_2], [-resource_2_per_prod_1, resource_1_per_prod_1]),\n im*vector(max_resource_1, max_resource_2)\n)", "description": "", "templateType": "anything", "can_override": false}, "valid_points": {"name": "valid_points", "group": "Marking", "definition": "filter(\n let([prod_1,prod_2],p,\n resource_1_per_prod_1 * prod_1 + resource_1_per_prod_2 * prod_2 <= max_resource_1\n and\n resource_2_per_prod_1 * prod_1 + resource_2_per_prod_2 * prod_2 <= max_resource_2\n ),\n p,\n points_to_consider\n)\n ", "description": "", "templateType": "anything", "can_override": false}, "revenue": {"name": "revenue", "group": "Marking", "definition": "map(\n prod_1_price * prod_1 + prod_2_price * prod_2,\n [prod_1,prod_2],\n valid_points\n)", "description": "", "templateType": "anything", "can_override": false}, "best_x,best_y": {"name": "best_x,best_y", "group": "Ungrouped variables", "definition": "let(\n i, filter(revenue[i]=top_revenue, i, 0..len(revenue)-1)[0],\n valid_points[i]\n)", "description": "", "templateType": "anything", "can_override": false}, "top_revenue": {"name": "top_revenue", "group": "Marking", "definition": "max(revenue)", "description": "", "templateType": "anything", "can_override": false}}, "variablesTest": {"condition": "", "maxRuns": 100}, "ungrouped_variables": ["resource_1_name, resource_2_name", "prod_1_name, prod_2_name", "resource_1_unit, resource_2_unit", "best_x,best_y"], "variable_groups": [{"name": "Setup", "variables": ["max_resource_1", "resource_1_per_prod_1", "resource_1_per_prod_2", "resource_2_per_prod_1", "resource_2_per_prod_2", "max_resource_2", "prod_1_price", "prod_2_price", "prod_1_max_production", "prod_2_max_production"]}, {"name": "Diagram", "variables": ["diagram"]}, {"name": "Marking", "variables": ["points_to_consider", "intersection", "valid_points", "revenue", "top_revenue"]}], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "student_prod_1: interpreted_answers[0]\n\nstudent_prod_2: interpreted_answers[1]\n\nstudent_revenue:\n student_prod_1 * prod_1_price + student_prod_2 * prod_2_price\n\nmark:\n correctif(student_revenue >= top_revenue)", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "

How many of each product should you make, in order to maximise your income? You can type your answer in the boxes below, or move the point on the diagram above.

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[[0]] {prod_1_name}

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[[1]] {prod_2_name}

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