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The polynomial remainder theorem is useful here, it states that the remainder of the division of a polynomial $f(x)$ by a linear polynomial $x-a$ is equal to $f(a)$.

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To find the quotient, here are two methods:

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1) Perform polynomial long division.

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2) First find the remainder by the polynomial remainder theorem. Minus the remainder from the initial polynomial, then factorise. 

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If you are unsure of the specific steps involved here, start by studying 'polynomial long division': http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-polydiv-2009-1.pdf and https://www.khanacademy.org/math/algebra2/arithmetic-with-polynomials/long-division-of-polynomials/v/polynomial-division are both useful resources.

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Next, study 'polynomial remainder theorem': https://www.khanacademy.org/math/algebra2/arithmetic-with-polynomials/polynomial-remainder-theorem/v/polynomial-remainder-theorem

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Find the quotient and remainder when $\\simplify{g(x) = x^3 - {a_coeff2}x^2+({a_coeff1})x -({a_coeff0}+{a_rmndr})}$ is divided by $\\simplify{x-{a_root1}}$

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Quotient $=$ [[0]]

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Remainder $=$ [[1]] 

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Hence write $g(x)$ in the form $g(x) = Q(x)(\\simplify{(x-{a_root1})}) + R$

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[[0]]$(\\simplify{x-{a_root1}})+$[[1]]

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By evaluating  $\\simplify{f(x)=x^3-{b_coeff2}x^2+{b_coeff1}x-{b_coeff0}}$ at an appropriate value of x, show that $\\simplify{x-{b_root1}}$ is a factor of $f(x)$

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$f($[[0]]$)=$[[1]]

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Hence factorise $\\simplify{f(x)=x^3-{b_coeff2}x^2+{b_coeff1}x-{b_coeff0}}$ completely

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By using the Polynomial Remainder Theorem, find the remainder when $\\simplify{f(x)=x^3+{c_coeff2}x^2+{c_coeff1}x+({c_coeff0}+ {c_r})}$ is divided by $\\simplify{(x-{c_root1})}$

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By using the Polynomial Remainder Theorem, find the remainder when $\\simplify{f(x)={d_coeff3}x^3+{d_coeff2}x^2+{d_coeff1}x+({d_coeff0}+ {d_r})}$ is divided by $\\simplify{(x-{d_root2})}$

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Find the quotient and remainder when $\\simplify{f(x)={e_coeff3}x^3+{e_coeff2}x^2+{e_coeff1}x+({e_coeff0}+ {e_r})}$ is divided by $\\simplify{({e_coeff3}x-{e_root1})}$

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Quotient $=$ [[0]]

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Remainder $=$ [[1]] 

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When $\\simplify{f(x)=x^3+px^2+{px}+{f0}}$ is divided by $\\simplify{x-{f_div}}$ the remainder is $\\var{f_r}$. Find the value of p.

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Remainder

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Quotient and remainder, polynomial division.

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