// Numbas version: exam_results_page_options {"name": "Distributive law: expanding one set of brackets", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Distributive law: expanding one set of brackets", "tags": ["Algebra", "algebra", "distributive law", "Expanding", "expanding", "expanding brackets"], "metadata": {"description": "

Things like \"expand 4(5a-3)\"

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The number in front of the bracket is multiplying the bracketed term, that is, each term in the brackets. Also, recall that a negative multiplied by a negative is a positive.

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$\\begin{align*}\\simplify{{nmult}({nxcoeff}a+{nconstant})}&=\\simplify[expandBrackets]{{nmult}({nxcoeff}a+{nconstant})}\\\\&=\\simplify[!noLeadingMinus]{{nmult*nxcoeff}a+{nmult*nconstant}}\\end{align*}$

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The expression $\\simplify{{nmult}({nxcoeff}a+{nconstant})}$ is factorised (written as a product). We can expand the expression (so it is written as a sum) to get 

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[[0]]$a$ + [[1]]

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