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Given \$x+\\var{a}=\\var{b}\$, we can rearrange the equation to that find \$x=\$ [[0]].

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Given \$x+\\var{a}=\\var{b}\$, we subtract \$\\var{a}\$ from both sides to get \$x\$ by itself.

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\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
 \$x+\\var{a}\$ \$=\$ \$\\var{b}\$ \$x+\\var{a}-\\var{a}\$ \$=\$ \$\\var{b}-\\var{a}\$ \$x\$ \$=\$ \$\\var{ans1}\$
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Given \$y-\\var{c}=\\var{d}\$,  \$y=\$ [[0]].

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Given \$y-\\var{c}=\\var{d}\$, we add \$\\var{c}\$ to both sides to get \$y\$ by itself.

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\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
 \$y-\\var{c}\$ \$=\$ \$\\var{d}\$ \$y-\\var{c}+\\var{c}\$ \$=\$ \$\\var{d}+\\var{c}\$ \$y\$ \$=\$ \$\\var{ans2}\$
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Rearrange \$\\var{f}+z=\\var{g}\$ to determine the value of \$z\$.

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\$z=\$ [[0]]

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Given \$\\var{f}+z=\\var{g}\$, we subtract \$\\var{f}\$ from both sides to get \$z\$ by itself.

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\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
 \$\\var{f}+z\$ \$=\$ \$\\var{g}\$ \$\\simplify[basic]{{f}+z-{f}}\$ \$=\$ \$\\simplify[basic]{{g}-{f}}\$ \$z\$ \$=\$ \$\\var{ans3}\$
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Solve \$\\var{h}=\\var{j}+a\$ for \$a\$.

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\$a=\$ [[0]]

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Given \$\\var{h}=\\var{j}+a\$, we subtract \$\\var{j}\$ from both sides to get \$a\$ by itself.

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\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
 \$\\var{h}\$ \$=\$ \$\\var{j}+a\$ \$\\simplify[basic]{{h}-{j}}\$ \$=\$ \$\\simplify[basic]{{j}+a-{j}}\$ \$\\var{ans4}\$ \$=\$ \$a\$ \$a\$ \$=\$ \$\\var{ans4}\$
\n

\n

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