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Given the first few terms of an arithmetic sequence, write down its formula, then find a couple of particular terms.
", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "In this question, consider the sequence
\n\\[ a = \\var{a1}, \\; \\var{a1+d}, \\; \\var{a1+d*2}, \\; \\var{a1+d*3}, \\; \\ldots \\]
\nA helpful person has drawn out a table of the terms so far.
\n$\\boldsymbol{n}$ | \n$1$ | \n$2$ | \n$3$ | \n$4$ | \n$\\ldots$ | \n
---|---|---|---|---|---|
$\\boldsymbol{a_n}$ | \n$\\var{a1}$ | \n$\\var{a1+d}$ | \n$\\var{a1+2d}$ | \n$\\var{a1+3d}$ | \n$\\ldots$ | \n
The formula for the $n^\\text{th}$ term, $a_n$, of an arithmetic sequence is
\n\\[ a_n=a_1+(n-1)d \\text{.} \\]
\n$a_1$ is the first term, and $d$ is the common difference between adjacent terms.
\nIn the given sequence, the common difference is $\\var{a1+d} - \\var{a1} = \\var{d}$, and the first term is $\\var{a1}$.
\nSo, the formula for this sequence is
\n\\[ a_n = \\var{a1} + (n-1) \\times \\var{d} \\text{.} \\]
\n\\[ a_\\var{small} = \\var{a1} + (\\var{small}-1) \\times \\var{d} = \\var{a1+(small-1)*d} \\text{.} \\]
\n\\[ a_\\var{large} = \\var{a1} + (\\var{large}-1) \\times \\var{d} = \\var{a1+(large-1)*d} \\text{.} \\]
\n\\[S_n = \\frac{n(a_1 + a_n)}{2}\\]
\nPlug in the values to get $S_{\\var{medium}} = \\frac{\\var{medium}(\\var{a1} + \\var{amed})}{2} = \\var{ansd} $
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\n$a_n =$ [[0]]
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Find the $\\var{small}^{\\text{th}}$ term
\n$a_{\\var{small}} = $ [[0]]
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Find the $\\var{large}^{\\text{th}}$ term
\n$a_{\\var{large}} = $[[0]]
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\n$S_{\\var{medium}} =$ [[0]]
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