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Simple application of \"Power Rule\" to differentiate single term functions.

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All co-efficients and powers are integer (though some may be negative.

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The Power Rule

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You can find the derivative for powers of functions using the following rule:

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If   \\( y=ax^n \\)  then   \\( \\frac{dy}{dx} = n \\times a x^{n-1} \\) 

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The Sum or Difference Rules

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The derivative of   \\( f(x) + g(x) \\)  is  \\(  \\frac{df}{dx} + \\frac{dg}{dx} \\)          and          the derivative of   \\( f(x) - g(x) \\)  is  \\(  \\frac{df}{dx} - \\frac{dg}{dx} \\)

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We are asked to differentiate a variety of functions, each consisting of a single term.

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We can do this using the \"Power Rule\" for differentiation:

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If   \\( y=ax^n \\)  then   \\( \\frac{dy}{dx} = n \\times a x^{n-1} \\)

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In plain language, \"multiply by the power, then reduce the power by one\".

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Then:

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a)

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\\( y= \\var{a_1} x^{\\var{n_1}} \\)

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\\( \\frac{dy}{dx } = \\var{n_1} \\times \\var{a_1} x^{\\var{n_1} - 1}                  \\)

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\\( \\frac{dy}{dx } = \\simplify{ {n_1}*{a_1}*x^{{n_1} - 1} } \\)

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b)

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\\( y= \\var{a_2} x^{\\var{n_2}} \\)

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\\( \\frac{dy}{dx } = \\var{n_2} \\times \\var{a_2} x^{\\var{n_2} - 1}                  \\)

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\\( \\frac{dy}{dx } = \\simplify{ {n_2}*{a_2}*x^{{n_2} - 1} } \\)

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c)

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\\( y= \\var{a_3} x^{\\var{n_3}} \\)

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\\( \\frac{dy}{dx } = \\var{n_3} \\times \\var{a_3} x^{\\var{n_3} - 1}                  \\)

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\\( \\frac{dy}{dx } = \\simplify{ {n_3}*{a_3}*x^{{n_3} - 1} } \\)

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Co-efficient for Q1

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Differentiate the following:

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\\( y= \\var{a_1} x^{\\var{n_1}} \\)

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\\( \\frac{dy}{dx } = \\)[[0]]

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\\( y= \\var{a_2} x^{\\var{n_2}} \\)

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\\( \\frac{dy}{dx } = \\) [[0]]

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\\( y= \\var{a_3} x^{\\var{n_3}} \\)

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\\( \\frac{dy}{dx } = \\)  [[0]]

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