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First we find the truth table for $\\var{a} \\var{op} \\var{b}$:
\n$p$ | $q$ | $r$ | $\\var{a} \\var{op} \\var{b}$ |
---|---|---|---|
$\\var{p[0]}$ | \n$\\var{q[0]}$ | \n$\\var{r[0]}$ | \n$\\var{ev1[0]}$ | \n
$\\var{p[1]}$ | \n$\\var{q[1]}$ | \n$\\var{r[1]}$ | \n$\\var{ev1[1]}$ | \n
$\\var{p[2]}$ | \n$\\var{q[2]}$ | \n$\\var{r[2]}$ | \n$\\var{ev1[2]}$ | \n
$\\var{p[3]}$ | \n$\\var{q[3]}$ | \n$\\var{r[3]}$ | \n$\\var{ev1[3]}$ | \n
$\\var{p[4]}$ | \n$\\var{q[4]}$ | \n$\\var{r[4]}$ | \n$\\var{ev1[4]}$ | \n
$\\var{p[5]}$ | \n$\\var{q[5]}$ | \n$\\var{r[5]}$ | \n$\\var{ev1[5]}$ | \n
$\\var{p[6]}$ | \n$\\var{q[6]}$ | \n$\\var{r[6]}$ | \n$\\var{ev1[6]}$ | \n
$\\var{p[7]}$ | \n$\\var{q[7]}$ | \n$\\var{r[7]}$ | \n$\\var{ev1[7]}$ | \n
Then the truth table for $\\var{a1} \\var{op2} \\var{b1}$:
\n$p$ | $q$ | $r$ | $\\var{a1} \\var{op2} \\var{b1}$ |
---|---|---|---|
$\\var{p[0]}$ | \n$\\var{q[0]}$ | \n$\\var{r[0]}$ | \n$\\var{ev2[0]}$ | \n
$\\var{p[1]}$ | \n$\\var{q[1]}$ | \n$\\var{r[1]}$ | \n$\\var{ev2[1]}$ | \n
$\\var{p[2]}$ | \n$\\var{q[2]}$ | \n$\\var{r[2]}$ | \n$\\var{ev2[2]}$ | \n
$\\var{p[3]}$ | \n$\\var{q[3]}$ | \n$\\var{r[3]}$ | \n$\\var{ev2[3]}$ | \n
$\\var{p[4]}$ | \n$\\var{q[4]}$ | \n$\\var{r[4]}$ | \n$\\var{ev2[4]}$ | \n
$\\var{p[5]}$ | \n$\\var{q[5]}$ | \n$\\var{r[5]}$ | \n$\\var{ev2[5]}$ | \n
$\\var{p[6]}$ | \n$\\var{q[6]}$ | \n$\\var{r[6]}$ | \n$\\var{ev2[6]}$ | \n
$\\var{p[7]}$ | \n$\\var{q[7]}$ | \n$\\var{r[7]}$ | \n$\\var{ev2[7]}$ | \n
Putting these together to find $(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$:
\n\n$p$ | $q$ | $r$ | $\\var{a} \\var{op} \\var{b}$ | $\\var{a1} \\var{op2} \\var{b1}$ | $(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$ |
---|---|---|---|---|---|
$\\var{p[0]}$ | \n$\\var{q[0]}$ | \n$\\var{r[0]}$ | \n$\\var{ev1[0]}$ | \n$\\var{ev2[0]}$ | \n$\\var{t_value[0]}$ | \n
$\\var{p[1]}$ | \n$\\var{q[1]}$ | \n$\\var{r[1]}$ | \n$\\var{ev1[1]}$ | \n$\\var{ev2[1]}$ | \n$\\var{t_value[1]}$ | \n
$\\var{p[2]}$ | \n$\\var{q[2]}$ | \n$\\var{r[2]}$ | \n$\\var{ev1[2]}$ | \n$\\var{ev2[2]}$ | \n$\\var{t_value[2]}$ | \n
$\\var{p[3]}$ | \n$\\var{q[3]}$ | \n$\\var{r[3]}$ | \n$\\var{ev1[3]}$ | \n$\\var{ev2[3]}$ | \n$\\var{t_value[3]}$ | \n
$\\var{p[4]}$ | \n$\\var{q[4]}$ | \n$\\var{r[4]}$ | \n$\\var{ev1[4]}$ | \n$\\var{ev2[4]}$ | \n$\\var{t_value[4]}$ | \n
$\\var{p[5]}$ | \n$\\var{q[5]}$ | \n$\\var{r[5]}$ | \n$\\var{ev1[5]}$ | \n$\\var{ev2[5]}$ | \n$\\var{t_value[5]}$ | \n
$\\var{p[6]}$ | \n$\\var{q[6]}$ | \n$\\var{r[6]}$ | \n$\\var{ev1[6]}$ | \n$\\var{ev2[6]}$ | \n$\\var{t_value[6]}$ | \n
$\\var{p[7]}$ | \n$\\var{q[7]}$ | \n$\\var{r[7]}$ | \n$\\var{ev1[7]}$ | \n$\\var{ev2[7]}$ | \n$\\var{t_value[7]}$ | \n
Next we find the truth table for $\\var{a2}$:
\n$\\var{c2}$ | $\\var{a2}$ |
---|---|
$\\var{d2[0]}$ | \n$\\var{ev3[0]}$ | \n
$\\var{d2[1]}$ | \n\n$\\var{ev3[1]}$ | \n
$\\var{d2[2]}$ | \n\n$\\var{ev3[2]}$ | \n
$\\var{d2[3]}$ | \n\n$\\var{ev3[3]}$ | \n
$\\var{d2[4]}$ | \n\n$\\var{ev3[4]}$ | \n
$\\var{d2[5]}$ | \n\n$\\var{ev3[5]}$ | \n
$\\var{d2[6]}$ | \n\n$\\var{ev3[6]}$ | \n
$\\var{d2[7]}$ | \n\n$\\var{ev3[7]}$ | \n
Putting this all together to obtain the truth table we want:
\n$p$ | $q$ | $r$ | $(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$ | $\\var{a2}$ | $((\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1}))\\var{op4}\\var{a2} $ |
---|---|---|---|---|---|
$\\var{p[0]}$ | \n$\\var{q[0]}$ | \n$\\var{r[0]}$ | \n$\\var{t_value[0]}$ | \n$\\var{ev3[0]}$ | \n$\\var{final_value[0]}$ | \n
$\\var{p[1]}$ | \n$\\var{q[1]}$ | \n$\\var{r[1]}$ | \n$\\var{t_value[1]}$ | \n$\\var{ev3[1]}$ | \n$\\var{final_value[1]}$ | \n
$\\var{p[2]}$ | \n$\\var{q[2]}$ | \n$\\var{r[2]}$ | \n$\\var{t_value[2]}$ | \n$\\var{ev3[2]}$ | \n$\\var{final_value[2]}$ | \n
$\\var{p[3]}$ | \n$\\var{q[3]}$ | \n$\\var{r[3]}$ | \n$\\var{t_value[3]}$ | \n$\\var{ev3[3]}$ | \n$\\var{final_value[3]}$ | \n
$\\var{p[4]}$ | \n$\\var{q[4]}$ | \n$\\var{r[4]}$ | \n$\\var{t_value[4]}$ | \n$\\var{ev3[4]}$ | \n$\\var{final_value[4]}$ | \n
$\\var{p[5]}$ | \n$\\var{q[5]}$ | \n$\\var{r[5]}$ | \n$\\var{t_value[5]}$ | \n$\\var{ev3[5]}$ | \n$\\var{final_value[5]}$ | \n
$\\var{p[6]}$ | \n$\\var{q[6]}$ | \n$\\var{r[6]}$ | \n$\\var{t_value[6]}$ | \n$\\var{ev3[6]}$ | \n$\\var{final_value[6]}$ | \n
$\\var{p[7]}$ | \n$\\var{q[7]}$ | \n$\\var{r[7]}$ | \n$\\var{t_value[7]}$ | \n$\\var{ev3[7]}$ | \n$\\var{final_value[7]}$ | \n
$p$ | $q$ | $r$ | $((\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1}))\\var{op4}\\var{a2} $ |
---|---|---|---|
$\\var{p[0]}$ | \n$\\var{q[0]}$ | \n$\\var{r[0]}$ | \n[[0]] | \n
$\\var{p[1]}$ | \n$\\var{q[1]}$ | \n$\\var{r[1]}$ | \n[[1]] | \n
$\\var{p[2]}$ | \n$\\var{q[2]}$ | \n$\\var{r[2]}$ | \n[[2]] | \n
$\\var{p[3]}$ | \n$\\var{q[3]}$ | \n$\\var{r[3]}$ | \n[[3]] | \n
$\\var{p[4]}$ | \n$\\var{q[4]}$ | \n$\\var{r[4]}$ | \n[[4]] | \n
$\\var{p[5]}$ | \n$\\var{q[5]}$ | \n$\\var{r[5]}$ | \n[[5]] | \n
$\\var{p[6]}$ | \n$\\var{q[6]}$ | \n$\\var{r[6]}$ | \n[[6]] | \n
$\\var{p[7]}$ | \n$\\var{q[7]}$ | \n$\\var{r[7]}$ | \n[[7]] | \n
Fyll ut sannhetstabellen for det logiske uttrykket: \\[((\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1}))\\var{op4}\\var{a2}\\] Tast inn S for sann og F for falsk.
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"bool_to_label(pre_ev2)", "templateType": "anything", "group": "Second Bracket", "name": "ev2", "description": ""}, "ev3": {"definition": "bool_to_label(pre_ev3)", "templateType": "anything", "group": "Last ", "name": "ev3", "description": ""}, "pre_ev2": {"definition": "map(evaluate(convch(a1)+\" \"+conv(op2)+\" \"+convch(b1),[bool_p[t],bool_q[t],bool_r[t]]),t,0..7)", "templateType": "anything", "group": "Second Bracket", "name": "pre_ev2", "description": ""}, "logic_symbol_list": {"definition": "[\"p\",\"q\",\"not p\",\"not q\",\"r\",\"not r\"]", "templateType": "anything", "group": "Lists of symbols", "name": "logic_symbol_list", "description": ""}, "pre_ev1": {"definition": "map(evaluate(convch(a)+\" \"+conv(op)+\" \"+convch(b),[bool_p[t],bool_q[t],bool_r[t]]),t,0..7)", "templateType": "anything", "group": "First Bracket", "name": "pre_ev1", "description": ""}, "a1": {"definition": "latex(latex_symbol_list[s[2]])", "templateType": "anything", "group": "Second Bracket", "name": "a1", "description": ""}, "a2": {"definition": "latex(random(\"\\\\neg p\",\"\\\\neg q\",\"\\\\neg r\"))", "templateType": "anything", "group": "Last ", "name": "a2", "description": ""}, "bool_r": {"definition": "list_to_boolean(list(logic_values[2]))", "templateType": "anything", "group": "Truth values", "name": "bool_r", "description": ""}, "bool_q": {"definition": "list_to_boolean(list(logic_values[1]))", "templateType": "anything", "group": "Truth values", "name": "bool_q", "description": ""}, "bool_p": {"definition": "list_to_boolean(list(logic_values[0]))", "templateType": "anything", "group": "Truth values", "name": "bool_p", "description": ""}, "a": {"definition": "latex(latex_symbol_list[s[0]])", "templateType": "anything", "group": "First Bracket", "name": "a", "description": ""}, "b": {"definition": "latex(latex_symbol_list[s[1]])", "templateType": "anything", "group": "First Bracket", "name": "b", "description": ""}, "pre_ev3": {"definition": "map(evaluate(convch(a2),[bool_p[t],bool_q[t],bool_r[t]]),t,0..7)", "templateType": "anything", "group": "Last ", "name": "pre_ev3", "description": ""}, "q": {"definition": "bool_to_label(list_to_boolean(list(logic_values[1])))", "templateType": "anything", "group": "Truth values", "name": "q", "description": ""}, "p": {"definition": "bool_to_label(list_to_boolean(list(logic_values[0])))", "templateType": "anything", "group": "Truth values", "name": "p", "description": ""}, "s": {"definition": "repeat(random(0..5),6)", "templateType": "anything", "group": "Lists of symbols", "name": "s", "description": ""}, "r": {"definition": "bool_to_label(list_to_boolean(list(logic_values[2])))", "templateType": "anything", "group": "Truth values", "name": "r", "description": ""}, "op": {"definition": "latex(random(\"\\\\lor\",\"\\\\land\",\"\\\\to\"))", "templateType": "anything", "group": "First Bracket", "name": "op", "description": ""}}, "metadata": {"notes": "", "description": "Create a truth table for a logical expression of the form $((a \\operatorname{op1} b) \\operatorname{op2}(c \\operatorname{op3} d))\\operatorname{op4}e $ where each of $a, \\;b,\\;c,\\;d,\\;e$ can be one the Boolean variables $p,\\;q,\\;r,\\;\\neg p,\\;\\neg q,\\;\\neg r$ and each of $\\operatorname{op1},\\;\\operatorname{op2},\\;\\operatorname{op3},\\;\\operatorname{op4}$ one of $\\lor,\\;\\land,\\;\\to$.
\nFor example: $((q \\lor \\neg r) \\to (p \\land \\neg q)) \\land \\neg r$
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