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To find common ratio $r$, we know term number $\\var{r2}$ divided by term number $\\var{r1}$ is $r^{\\var{r2}-\\var{r1}}$. It is then easy to find the common ratio.

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To find the $n$th term, multiply the first term a by the common ratio r to the power of n-1, ie ${a}{r^{n-1}}$

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In a geometric series, term number $\\var{r1}$ is $\\simplify{{t1}/{td}^{r1}}$ and term number $\\var{r2}$ is $\\simplify{{t1}/{td}^{r2}}$. 

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What is term number $\\var{r3}$? Give your answer to 2 decimal places.

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In a gemetric series the first term is $\\var{a}$, and the $\\var{tr}$ th term is $\\var{nthterm}$. Assumming the common ration $r$ is positive, find the sum to infinity. Give your answer to 2 decimal places. 

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the first term for part two

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the common ratio for part two

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