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Complete the following truth table:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$p$$q$$\\var{a} \\var{op} \\var{b}$$\\var{a1} \\var{op2} \\var{b1}$$(\\var{a} \\var{op} \\var{b}) \\var{op1} (\\var{a1} \\var{op2} \\var{b1})$
$\\var{disp[0]}$$\\var{disq[0]}$[[0]][[4]][[8]]
$\\var{disp[1]}$$\\var{disq[1]}$[[1]][[5]][[9]]
$\\var{disp[2]}$$\\var{disq[2]}$[[2]][[6]][[10]]
$\\var{disp[3]}$$\\var{disq[3]}$[[3]][[7]][[11]]
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In the following question you are asked to construct a truth table for:

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\\[(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1}).\\]

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\n

Enter T if true, else enter F.

\n

\n

\n

\n

\n

\n

\n

\n

\n

\n

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", "tags": [], "question_groups": [{"pickingStrategy": "all-ordered", "questions": [], "name": "", "pickQuestions": 0}], "preamble": {"css": "", "js": ""}, "type": "question", "metadata": {"notes": "", "licence": "Creative Commons Attribution 4.0 International", "description": "

Create a truth table for a logical expression of the form $(a \\operatorname{op1} b) \\operatorname{op2}(c \\operatorname{op3} d)$ where $a, \\;b,\\;c,\\;d$ can be the Boolean variables $p,\\;q,\\;\\neg p,\\;\\neg q$ and each of $\\operatorname{op1},\\;\\operatorname{op2},\\;\\operatorname{op3}$ one of $\\lor,\\;\\land,\\;\\to$.

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For example: $(p \\lor \\neg q) \\land(q \\to \\neg p)$.

"}, "advice": "

First we find the truth table for $\\var{a} \\var{op} \\var{b}$:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$p$$q$$\\var{a} \\var{op} \\var{b}$
$\\var{disp[0]}$$\\var{disq[0]}$$\\var{ev1[0]}$
$\\var{disp[1]}$$\\var{disq[1]}$$\\var{ev1[1]}$
$\\var{disp[2]}$$\\var{disq[2]}$$\\var{ev1[2]}$
$\\var{disp[3]}$$\\var{disq[3]}$$\\var{ev1[3]}$
\n

Then the truth table for $\\var{a1} \\var{op2} \\var{b1}$:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$p$$q$$\\var{a1} \\var{op2} \\var{b1}$
$\\var{disp[0]}$$\\var{disq[0]}$$\\var{ev2[0]}$
$\\var{disp[1]}$$\\var{disq[1]}$$\\var{ev2[1]}$
$\\var{disp[2]}$$\\var{disq[2]}$$\\var{ev2[2]}$
$\\var{disp[3]}$$\\var{disq[3]}$$\\var{ev2[3]}$
\n

Putting these together to find $(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$:

\n

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\var{a} \\var{op} \\var{b}$$\\var{a1} \\var{op2} \\var{b1}$$(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$
$\\var{ev1[0]}$$\\var{ev2[0]}$$\\var{t_value[0]}$
$\\var{ev1[1]}$$\\var{ev2[1]}$$\\var{t_value[1]}$
$\\var{ev1[2]}$$\\var{ev2[2]}$$\\var{t_value[2]}$
$\\var{ev1[3]}$$\\var{ev2[3]}$$\\var{t_value[3]}$
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