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$\\operatorname{P}(T \\lt \\var{v1})$ where $T \\sim t_{\\var{t}}$

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$\\operatorname{P}(T \\lt \\var{v1})=\\;$?[[0]]

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$\\operatorname{P}(T \\lt \\var{-v2})$ where $T \\sim t_{\\var{tn}}$

\n

$\\operatorname{P}(T \\lt \\var{-v2})=\\;$ [[0]]

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$\\operatorname{P}(T \\gt \\var{v3})$ where $T \\sim t_{\\var{tm}}$

\n

$\\operatorname{P}(T \\gt \\var{v3})=\\;$?[[0]]

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Use statistics tables or R to find the following:

\n

 

", "tags": ["MAS2302", "checked2015", "critical values", "one-sided", "statistics", "student", "student ", "t statistics", "t tables", "t test", "tables"], "rulesets": {}, "preamble": {"css": "", "js": ""}, "type": "question", "metadata": {"notes": "

27/01/2013:

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First draft completed.

", "licence": "Creative Commons Attribution 4.0 International", "description": "

Looking up t-tables. 

"}, "advice": "

 

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a)

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We have to find  $\\operatorname{P}(T \\lt \\var{v1})$ where $T \\sim t_{\\var{t}}$.

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Looking at the tables for degrees of freedom $\\var{t}$ ,

\n

{table([cr(t)],per)} we see that the value $\\var{v1}$  corresponds to the $\\var{p1}$ critical point, and since the  tables are one sided we see that $\\operatorname{P}(T \\lt \\var{v1})=\\var{p1}$ 

\n

 

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 b)

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We have to find $\\operatorname{P}(T \\lt \\var{-v2})$ where $T \\sim t_{\\var{tn}}$. Looking at the table for degrees of freedom $\\var{tn}$ ,

\n

{table([cr(tn)],per)} we see that since the tables are one sided, 

\n

$\\operatorname{P}(T \\lt \\var{-v2})=\\operatorname{P}(T \\gt \\var{v2})=1-\\operatorname{P}(T \\lt \\var{v2})=1-\\var{precround(1-p2,3)}=\\var{p2}$ 

\n

 c)

\n

We have to find $\\operatorname{P}(T \\gt \\var{v3})$ where $T \\sim t_{\\var{tm}}$. Looking at the table for degrees of freedom $\\var{tm}$ ,

\n

{table([cr(tm)],per)} we see that since the tables are one sided, 

\n

$\\operatorname{P}(T \\gt \\var{v3})=1-\\operatorname{P}(T \\lt \\var{v3})=1-\\var{precround(1-p3,3)}=\\var{p3}$ 

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