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For every $\\var{ep} \\gt 0$ , there exists a $\\var{del} \\gt 0$ such that $\\left |f(x)-a\\right | \\lt \\var{ep}$ whenever $0 \\lt |x-x_0| \\lt \\var{del}$ and $x \\in I$.

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For every $\\var{del} \\gt 0$ , there exists a $\\var{ep} \\gt 0$ such that $\\left |f(x)-a\\right | \\lt \\var{ep}$ whenever $0 \\lt |x-x_0| \\lt \\var{del}$ and $x \\in I$.

", "

For every $\\var{ep} \\gt 0$ , there exists a $\\var{del} \\gt 0$ such that $\\left |f(x)-a\\right | \\lt \\var{del}$ whenever $0 \\lt |x-x_0| \\lt \\var{ep}$ and $x \\in I$.

", "

For every $\\var{ep} \\gt 0$ , there exists a $\\var{del} \\gt 0$ such that $\\left |f(x)-f(x_0)\\right | \\lt \\var{ep}$ whenever $0 \\lt |x-a| \\lt \\var{del}$ and $x \\in I$.

", "

For every $\\var{del} \\gt 0$ , there exists a $\\var{ep} \\gt 0$ such that $\\left |f(x)-a\\right | \\gt \\var{del}$ whenever $0 \\lt |x-x_0| \\lt \\var{ep}$ and $x \\in I$.

", "

For every $\\var{ep} \\gt 0$ , there exists a $\\var{del} \\gt 0$ such that $\\left |f(x)-a\\right | \\lt \\var{ep}$ whenever $0 \\lt |x-x_0| \\gt \\var{del}$ and $x \\in I$.

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Choose one of the following as the correct definition:

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Let $x_0$ be a point in the open interval $I \\subset \\mathbb{R}$ and let $f:I \\setminus \\{x_0\\} \\rightarrow \\mathbb{R}$ be a function.

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What does it mean to say that $f(x) \\rightarrow a$ as $x \\rightarrow x_0$?

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