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$r=$ [[0]] (Enter your answer to 3 d.p.)

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$\\theta=$ [[0]] (Enter your answer to 3 d.p.)

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Write the complex number $z=\\var{z}$ in polar form $z=r\\mathrm{e}^{i\\theta}$, with $r>0$, $-\\pi<\\theta\\leqslant\\pi$, by calculating $r$ and $\\theta$.

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Polar form of a complex number.

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To write a complex number $z=a+bi$ in polar form $z=r\\mathrm{e}^{i\\theta}$, we calculate the modulus $r = \\lvert z \\rvert$ and argument $\\theta = \\arg(z)$.

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Hence

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\\[r=\\lvert z \\rvert=\\sqrt{a^2+b^2}=\\sqrt{(\\var{a})^2+(\\var{b})^2}=\\var{absz}\\;\\text{to 3d.p.}\\]

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and, in general,

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\\[\\theta=\\arg(z)=\\arctan\\left(\\frac{b}{a}\\right).\\]

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If $a=0$, however, then $\\mathrm{Re}(z)=0$, so $\\arg(z)=\\pm\\frac{\\pi}{2}$, depending on whether $\\mathrm{Im}(z)$ is positive or negative.

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In this case $a=\\var{a}$, and $b=\\var{b}$, so $\\arg(z)=\\var{argz}$.

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