// Numbas version: finer_feedback_settings {"name": "Principle value of a complex number", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variable_groups": [], "variables": {"v": {"group": "Ungrouped variables", "templateType": "anything", "definition": "precround(exp(-b1*pi/4)*sin(b1*ln(a1*sqrt(2))),3)", "name": "v", "description": ""}, "tol": {"group": "Ungrouped variables", "templateType": "anything", "definition": "0.001", "name": "tol", "description": ""}, "u": {"group": "Ungrouped variables", "templateType": "anything", "definition": "precround(exp(-b1*pi/4)*cos(b1*ln(a1*sqrt(2))),3)", "name": "u", "description": ""}, "a1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "random(1..4)", "name": "a1", "description": ""}, "b1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "random(1..4)", "name": "b1", "description": ""}}, "ungrouped_variables": ["a1", "u", "b1", "tol", "v"], "rulesets": {}, "name": "Principle value of a complex number", "showQuestionGroupNames": false, "functions": {}, "parts": [{"scripts": {}, "gaps": [{"showPrecisionHint": false, "allowFractions": false, "scripts": {}, "type": "numberentry", "correctAnswerFraction": false, "minValue": "u-tol", "showCorrectAnswer": true, "marks": 1, "maxValue": "u+tol"}, {"showPrecisionHint": false, "allowFractions": false, "scripts": {}, "type": "numberentry", "correctAnswerFraction": false, "minValue": "v-tol", "showCorrectAnswer": true, "marks": 1, "maxValue": "v+tol"}], "type": "gapfill", "showCorrectAnswer": true, "prompt": "

$u=$ [[0]].  (Enter your answer to 3d.p.)

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$v=$ [[1]].  (Enter your answer to 3d.p.)

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Find the principal value of the complex number $z=(\\simplify{{a1}+i*{a1}})^{\\simplify{i*{b1}}}$, in the form $u+iv$.

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15/7/2012:

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Added tags.

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Calculate the principal value of a complex number.

"}, "advice": "

The complex number $z=(a+bi)^n$ can be written in the form

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\\[z=r^n\\mathrm{e}^{in\\left(\\theta+2k\\pi\\right)},\\]

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where $r$ is the modulus of $a+bi$, $\\theta$ is the argument, and where $-\\pi<\\theta\\leqslant\\pi$, and $k=0,1,2,\\ldots$.

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The principal value of $z$ is that which corresponds to $k=0$, so in this question

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\\[z=(\\simplify{{a1}+i*{a1}})^{\\simplify{i*{b1}}}=r^{\\simplify{i*{b1}}}\\mathrm{e}^{\\simplify{{-b1}*theta}}.\\]

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Then, $r$ is given by

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\\[r=\\sqrt{(\\var{a1})^2+(\\var{a1})^2}=\\simplify{{a1}*sqrt(2)},\\]

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and the argument $\\theta$ is given by

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\\[\\theta=\\arctan\\left(\\frac{\\var{a1}}{\\var{a1}}\\right)=\\arctan(1)=\\frac{\\pi}{4}.\\]

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Therefore

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\\[z=(\\simplify{{a1}*sqrt(2)})^{\\simplify{i*{b1}}}\\mathrm{e}^{\\simplify{{-b1}*pi/4}}.\\]

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Next, note that

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\\[(\\simplify{{a1}*sqrt(2)})^{\\simplify{i*{b1}}}=\\mathrm{e}^{\\simplify{i*{b1}}\\ln(\\simplify{{a1}*sqrt(2)})}.\\]

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Now use the identity

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\\[\\mathrm{e}^{i\\phi}=\\cos(\\phi)+i\\sin(\\phi),\\]

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so

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\\[(\\simplify{{a1}*sqrt(2)})^{\\simplify{i*{b1}}}\\mathrm{e}^{\\simplify{{-b1}*pi/4}}=\\Biggl(\\cos\\biggl(\\simplify{{b1}*ln({a1}*sqrt(2))}\\biggr)+i\\sin\\biggl(\\simplify{{b1}*ln({a1}*sqrt(2))}\\biggr)\\Biggr)\\mathrm{e}^{\\simplify{{-b1}*pi/4}}\\]

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which, when evaluated numerically gives

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\\[z=\\simplify{{u}+{v}i}\\;\\text{to 3d.p.}\\]

", "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}]}]}], "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}]}