// Numbas version: exam_results_page_options {"name": "Solve a constant coefficient second order ODE ", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Solve a constant coefficient second order ODE ", "tags": ["checked2015"], "metadata": {"description": "

Find the solution of a constant coefficient second order ordinary differential equation of the form $ay''+by=0$. Complex roots.

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

The general solution of the differential equation

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\\[\\simplify{{a1}*y''+{b1}*y}=0\\]

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can be written in the form

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\\[y(x)=A\\cos(\\lvert\\lambda_1\\rvert x)+B\\sin(\\lvert\\lambda_2\\rvert x),\\]

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where $A,B\\in\\mathbb{R}$, and $\\lambda_1,\\lambda_2\\in\\mathbb{C}$.

", "advice": "

a)

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We can solve the differential equation by making the assumption that $y=\\mathrm{e}^{\\lambda x}$.

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By substituting this expression for $y$ into the equation, and cancelling terms in $\\mathrm{e}^{\\lambda x}$ (which we can do, because $\\mathrm{e}^{\\lambda x}\\ne 0$), we obtain

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\\[\\simplify{{a1}*lambda^2+{b1}}=0,\\]

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which has solutions

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\\[\\lambda_{1,2}=\\pm\\simplify{sqrt({b1}/{a1})}i.\\]

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The general solution to the differential equation, therefore, is

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\\[y(x)=A\\cos\\left(\\simplify{sqrt({b1})/sqrt({a1})*x}\\right)+B\\sin\\left(\\simplify{sqrt({b1})/sqrt({a1})*x}\\right).\\]

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This is the only form of the solution accepted in this question, but note that the general solution could also be written as

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\\[y(x)=A\\cos\\left(\\simplify{sqrt({b1})/sqrt({a1})*x}\\right)+B\\sin\\left(\\simplify{-sqrt({b1})/sqrt({a1})*x}\\right),\\]

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or

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\\[y(x)=A\\cos\\left(\\simplify{-sqrt({b1})/sqrt({a1})*x}\\right)+B\\sin\\left(\\simplify{sqrt({b1})/sqrt({a1})*x}\\right).\\]

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These forms just redefine what is meant by the constants $A$ and $B$, however, since

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\\[\\cos(-x)=\\cos(x)\\quad\\text{and}\\quad\\sin(-x)=-\\sin(x).\\]

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b)

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Applying the conditions $y(0)=\\var{c1}$ and $y'(0)=\\var{d1}$ gives

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\\[\\var{c1}=y(0)=A\\]

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and

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\\[\\var{d1}=y'(0)=\\simplify{B*(sqrt({b1})/sqrt({a1}))}.\\]

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So $A=\\var{c1}$, and $B=\\simplify{{d1}*sqrt({a1}/{b1})}$.

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Solve the differential equation, and enter the values of $\\lvert\\lambda_1\\rvert$ and $\\lvert\\lambda_2\\rvert$ in the boxes.

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Do not enter decimals in your answers. If you need to enter a square root, e.g. $\\sqrt{x}$, enter this as sqrt(x).

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$\\lvert\\lambda_1\\rvert=$ [[0]]

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$\\lvert\\lambda_2\\rvert=$ [[1]]

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Do not enter decimals in your answer.

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Now, using the general form of solution as shown above, with $\\lvert\\lambda_1\\rvert$ and $\\lvert\\lambda_2\\rvert$, find the exact solution that satisfies the conditions $y(0)=\\var{c1}$ and $y'(0)=\\var{d1}$, by calculating the values of the constants $A$ and $B$, and entering them in the boxes.

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Do not enter decimals in your answers. If you need to enter a square root, e.g. $\\sqrt{x}$, enter this as sqrt(x).

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$A=$ [[0]]

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$B=$ [[1]]

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Do not enter decimals in your answer.

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