// Numbas version: finer_feedback_settings {"name": "Solve a constant coefficient second order ODE, ", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variable_groups": [], "variables": {"correctform": {"group": "Ungrouped variables", "templateType": "anything", "definition": "switch (\n disc>0, forms[0],\n disc=0, forms[1],\n disc<0, forms[2]\n )", "description": "", "name": "correctform"}, "ltgteq": {"group": "Ungrouped variables", "templateType": "anything", "definition": "switch (\n disc>0, \"greater than\",\n disc=0, \"equal to\",\n disc<0, \"less than\"\n )", "description": "", "name": "ltgteq"}, "c1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "random(-9..9 except 0)", "description": "", "name": "c1"}, "disc": {"group": "Ungrouped variables", "templateType": "anything", "definition": "b1^2-4*a1*c1", "description": "", "name": "disc"}, "incorrectform": {"group": "Ungrouped variables", "templateType": "anything", "definition": "switch (\n disc>0, [forms[1],forms[2]],\n disc=0, [forms[0],forms[2]],\n disc<0, [forms[0],forms[1]]\n )", "description": "", "name": "incorrectform"}, "b1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "random(-9..9 except 0)", "description": "", "name": "b1"}, "lambda2": {"group": "Ungrouped variables", "templateType": "anything", "definition": "precround((-b1-sqrt(disc))/(2*a1),3)", "description": "", "name": "lambda2"}, "a1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "random(1..9)", "description": "", "name": "a1"}, "lambda1": {"group": "Ungrouped variables", "templateType": "anything", "definition": "precround((-b1+sqrt(disc))/(2*a1),3)", "description": "", "name": "lambda1"}, "forms": {"group": "Ungrouped variables", "templateType": "anything", "definition": "[\"$A\\\\mathrm{e}^{\\\\lambda_1 x}+B\\\\mathrm{e}^{\\\\lambda_2 x}$\",\"$(A+Bx)\\\\mathrm{e}^{\\\\lambda x}$\",\"$\\\\mathrm{e}^{\\\\alpha x}\\\\biggl(A\\\\cos(\\\\beta x)+B\\\\sin(\\\\beta x)\\\\biggr)$\"]", "description": "", "name": "forms"}}, "ungrouped_variables": ["a1", "correctform", "incorrectform", "forms", "disc", "b1", "c1", "lambda1", "lambda2", "ltgteq"], "name": "Solve a constant coefficient second order ODE, ", "functions": {}, "preamble": {"css": "", "js": ""}, "parts": [{"displayType": "radiogroup", "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "showCellAnswerState": true, "choices": ["

{correctform}

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{incorrectform[0]}

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{incorrectform[1]}

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Which of the following choices defines the form of the general solution of the differential equation?

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In each case $A$ and $B$ are arbitrary constants, and $\\lambda_1$, $\\lambda_2$, $\\lambda$, $\\alpha$, and $\\beta$ are other constants arising from the solution of the auxiliary equation (their actual values are not important for this part of the question).

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Find the general solution of the differential equation, by setting up an appropriate auxiliary equation, solving it, and entering the solutions  $\\lambda_1$ and $\\lambda_2$  of the auxiliary equation in the boxes.  If the solutions are real and distinct, enter the greatest solution as $\\lambda_1$; if the solutions are repeated, enter the same values for $\\lambda_1$ and $\\lambda_2$; if the solutions are complex, enter the solution with the greatest imaginary part as $\\lambda_1$.

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Enter your answers to 3 d.p.

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$\\lambda_1=$ [[0]]

\n

$\\lambda_2=$ [[1]]

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You are given the differential equation

\n

\\[\\simplify{{a1}*y''+{b1}*y'+{c1}*y=0}.\\]

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Find the solution of a constant coefficient second order ordinary differential equation of the form $ay''+by'+cy=0$.

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To determine the form of the general solution of the equation

\n

\\[ay''+by'+c=0,\\]

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first set $y=\\mathrm{e}^{\\lambda x}$, and substitute to obtain

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\\[a\\lambda^2+b\\lambda+c=0,\\]

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for which the solutions are

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\\[\\lambda_{1,2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}.\\]

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If $b^2-4ac>0$, then the roots are real and distinct, and the solution takes the form

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\\[y(x)=\\var{forms[0]}.\\]

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If $b^2-4ac=0$, then the roots are real and repeated, and the solution takes the form

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\\[y(x)=\\var{forms[1]}.\\]

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If $b^2-4ac<0$, then the roots are complex, and the solution takes the form

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\\[y(x)=\\var{forms[2]},\\]

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where $\\lambda_1=\\alpha+i\\beta$ and $\\lambda_2=\\alpha-i\\beta$.

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a)

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In this question we have $\\simplify{{a1}*y''+{b1}*y'+{c1}*y=0}$, and then

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\\[b^2-4ac=\\var{b1^2}-4\\times(\\var{a1*c1})=\\var{disc},\\]

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which is {ltgteq} zero, so the general solution takes the form

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\\[y(x)=\\var{correctform}.\\]

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b)

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Making the substitution $y=\\mathrm{e}^{\\lambda x}$, then gives

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\\[\\simplify{{a1}*lambda^2+{b1}*lambda+{c1}=0},\\]

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which has solutions

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\\[\\lambda_1=\\frac{\\var{-b1}+\\sqrt{\\var{disc}}}{\\var{2*a1}}=\\var{lambda1} \\text{ to 3 d.p.,}\\]

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and

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\\[\\lambda_2=\\frac{\\var{-b1}-\\sqrt{\\var{disc}}}{\\var{2*a1}}=\\var{lambda2} \\text{ to 3 d.p.}\\]

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