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\n", "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "useCustomName": false, "customName": "", "unitTests": [], "showFeedbackIcon": true, "scripts": {}, "gaps": [{"answer": "{sort(essential_points)}", "useCustomName": false, "customMarkingAlgorithm": "", "checkingType": "absdiff", "extendBaseMarkingAlgorithm": true, "showPreview": true, "customName": "", "checkVariableNames": false, "unitTests": [], "valuegenerators": [], "vsetRange": [0, 1], "marks": 1, "showFeedbackIcon": true, "scripts": {"mark": {"script": "var os = this.studentAnswer;\nvar oc = this.settings.correctAnswer;\nthis.studentAnswer = 'set('+this.studentAnswer+')';\nthis.settings.correctAnswer = 'set('+this.settings.correctAnswer+')';\nJMEPart.prototype.mark.apply(this);\n\nthis.studentAnswer = os;\nthis.settings.correctAnswer = oc;", "order": "instead"}}, "vsetRangePoints": 5, "type": "jme", "variableReplacementStrategy": "originalfirst", "checkingAccuracy": 0.001, "showCorrectAnswer": true, "variableReplacements": [], "failureRate": 1}], "type": "gapfill", "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "variableReplacements": [], "marks": 0, "sortAnswers": false}], "variablesTest": {"condition": "", "maxRuns": 100}, "statement": "Find and classify all the singular points (excluding the point at infinity) of the equation
\n\\[ \\var{latex(y'')} + \\var{latex(y')} + \\var{latex(y)} = 0 \\]
\nEnter your answer for each part as a list of numbers, separated by commas and enclosed in square brackets. For example, if $8$ and $9$ were regular singular points, you would enter [8,9]
. If there are no points, enter []
.
Trying out something: get the student to enter a set for each of \"regular singular points\" and \"essential singular points\".
\nFind and classify singular points of a second-order ordinary differential equation. One equation is chosen from a selection of 10.
"}, "advice": "First write the equation in the form
\n\\[y''+p(x)y'+q(x)y=0,\\]
\nso we have
\n\\[ y'' + \\var{latex(coefficient(points,p,'y\\''))} + \\var{latex(coefficient(points,q,'y'))} = 0 \\]
\nThat is,
\n\\begin{align}
p(x) &= \\var{latex(coefficient(points,p,''))}, & q(x) &= \\var{latex(coefficient(points,q,''))}.
\\end{align}
This equation has no singular points, i.e. all points are analytic.
\n$x = \\var{singular_points[0]}$ is a singular point of the equation. This is a regular essential point if both $(\\simplify{x-{singular_points[0]}})p(x)$ and $(\\simplify{x-{singular_points[0]}})^2q(x)$ are analytic at $x = \\var{singular_points[0]}$.
\nSo first form
\n\\[ (\\simplify[]{x-{singular_points[0]}})p(x) = \\var{latex(coefficient(points,[p[0]+1]+p[1..len(p)],''))} \\]
\nThis is {if(p[0]+1>=0,\"analytic\",\"singular\")} at $x = \\var{singular_points[0]}$.
\nNext, form
\n\\[ (\\simplify[]{x-{singular_points[0]}})^2q(x) = \\var{latex(coefficient(points,[q[0]+2]+q[1..len(q)],''))} \\]
\nThis is {if(q[0]+2>=0,\"analytic\",\"singular\")} at $x = \\var{singular_points[0]}$.
\nHence $x = \\var{singular_points[0]}$ is {if(is_essential[0],\"an essential\",\"a regular\")} singular point.
\n$x = \\var{singular_points[1]}$ is another singular point of the equation, so form
\n\\[ (\\simplify[]{x-{singular_points[1]}})p(x) = \\var{latex(coefficient(points,[p[0],p[1]+1]+p[2..len(p)],''))} \\]
\nThis is {if(p[1]+1>=0,\"analytic\",\"singular\")} at $x = \\var{singular_points[1]}$.
\nNext, form
\n\\[ (\\simplify[]{x-{singular_points[1]}})^2q(x) = \\var{latex(coefficient(points,[q[0],q[1]+2]+q[2..len(q)],''))} \\]
\nThis is {if(q[1]+2>=0,\"analytic\",\"singular\")} at $x = \\var{singular_points[1]}$.
\nHence $x = \\var{singular_points[1]}$ is {if(is_essential[1],\"an essential\",\"a regular\")} singular point.
\n