// Numbas version: exam_results_page_options {"name": "Parameterisation of a curve - tangent and coordinates at given point, ", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variablesTest": {"condition": "", "maxRuns": 100}, "variables": {"speed": {"templateType": "anything", "group": "Ungrouped variables", "definition": "precround(sqrt(dxdtd^2+b^2),2)", "description": "", "name": "speed"}, "x": {"templateType": "anything", "group": "Ungrouped variables", "definition": "c^a", "description": "", "name": "x"}, "d": {"templateType": "anything", "group": "Ungrouped variables", "definition": "random(1..9)", "description": "", "name": "d"}, "b": {"templateType": "anything", "group": "Ungrouped variables", "definition": "random(1..10)*sign(random(1,-1))", "description": "", "name": "b"}, "c": {"templateType": "anything", "group": "Ungrouped variables", "definition": "random(1..6)", "description": "", "name": "c"}, "dxdtd": {"templateType": "anything", "group": "Ungrouped variables", "definition": "a*d^(a-1)", "description": "", "name": "dxdtd"}, "dxdtc": {"templateType": "anything", "group": "Ungrouped variables", "definition": "a*c^(a-1)", "description": "", "name": "dxdtc"}, "a": {"templateType": "anything", "group": "Ungrouped variables", "definition": "random(2..4)", "description": "", "name": "a"}, "y": {"templateType": "anything", "group": "Ungrouped variables", "definition": "b*c", "description": "", "name": "y"}}, "ungrouped_variables": ["a", "c", "b", "d", "dxdtc", "dxdtd", "y", "x", "speed"], "rulesets": {}, "name": "Parameterisation of a curve - tangent and coordinates at given point, ", "showQuestionGroupNames": false, "variable_groups": [], "parts": [{"scripts": {}, "gaps": [{"showCorrectAnswer": true, "showPrecisionHint": false, "allowFractions": false, "scripts": {}, "type": "numberentry", "correctAnswerFraction": false, "minValue": "x", "maxValue": "x", "marks": 1}, {"showCorrectAnswer": true, "showPrecisionHint": false, "allowFractions": false, "scripts": {}, "type": "numberentry", "correctAnswerFraction": false, "minValue": "y", "maxValue": "y", "marks": 1}], "type": "gapfill", "prompt": "

Find the coordinates $\\pmatrix{x,y}$ of the point corresponding to $t=\\var{c}$.

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$\\pmatrix{x,y}=($[[0]]$,$[[1]]$)$.

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Find the components of the tangent vector $\\boldsymbol{u}\\equiv\\pmatrix{\\frac{\\mathrm{d}x}{\\mathrm{d}t},\\frac{\\mathrm{d}y}{\\mathrm{d}t}}$.

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$\\boldsymbol{u}=($[[0]]$,$[[1]]$)$.

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The components of the same tangent vector, given $t=\\var{c}$.

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$\\boldsymbol{u}|_{t=\\var{c}}=($[[2]]$,$[[3]]$)$.

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Interpreting $t$ as time, and hence the tangent vector $\\boldsymbol{u}$ as velocity, find the speed $u=|\\boldsymbol{u}|$ at $t=\\var{d}$.

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$u=$ [[0]].  (Enter your answer to 2d.p.)

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You are given the following curve, $t\\rightarrow\\pmatrix{t^\\var{a},\\simplify{{b}t}}$, defined with respect to the parameter $t$.

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Parametric form of a curve, cartesian points, tangent vector, and speed.

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a)

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To find the coordinates of the point corresponding to $t=\\var{c}$, substitute $t=\\var{c}$ into the expression for the curve, i.e.

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\\[\\pmatrix{x,y}=\\pmatrix{\\var{c}^\\var{a},\\var{b}\\times\\var{c}}=\\pmatrix{\\var{x},\\var{y}}.\\]

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b)

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Differentiate each component of the vector in part a) to find the tangent vector $\\boldsymbol{u}$, i.e.

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\\[\\boldsymbol{u}=\\pmatrix{\\frac{\\mathrm{d}}{\\mathrm{d}t}t^\\var{a},\\frac{\\mathrm{d}}{\\mathrm{d}t}\\simplify{{b}t}}=\\pmatrix{\\var{a}t^\\var{a-1},\\var{b}}.\\]

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The tangent vector at $t=\\var{c}$ is found by substituting $t=\\var{c}$ into the tangent vector $\\boldsymbol{u}$, i.e.

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\\[\\boldsymbol{u}\\vert_{t=\\var{c}}=\\pmatrix{\\var{a}\\times\\var{c}^\\var{a-1},\\var{b}}=\\pmatrix{\\var{dxdtc},\\var{b}}.\\]

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c)

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The velocity $u$ is given by $u=\\lvert\\boldsymbol{u}\\rvert=\\sqrt{\\left(\\frac{\\mathrm{d}x}{\\mathrm{d}t}\\right)^2+\\left(\\frac{\\mathrm{d}y}{\\mathrm{d}t}\\right)^2}$.  We must calculate the speed at $t=\\var{d}$, however, therefore

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\\[u\\vert_{t=\\var{d}}=\\sqrt{\\left(\\var{a}\\times\\var{d}^\\var{a-1}\\right)^2+\\var{b}^2}=\\sqrt{\\var{dxdtd^2}+\\var{b^2}}=\\var{speed} \\; \\text{to 2d.p.}\\]

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