// Numbas version: exam_results_page_options {"name": "Solving a monic quadratic by factorising", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"functions": {}, "ungrouped_variables": ["a", "b", "linear", "const", "monicsoln"], "name": "Solving a monic quadratic by factorising", "tags": ["binomial", "factorisation", "Factorisation", "factorising", "factors", "Factors", "monic", "quadratic", "quadratics", "solving"], "preamble": {"css": "", "js": ""}, "advice": "", "rulesets": {}, "parts": [{"stepsPenalty": "1", "prompt": "
Solve the following quadratic by factorisation:
\n\n | $\\simplify{x^2+{linear}x+{const}}$ | \n$=$ | \n0 | \n
$\\Longrightarrow$ | \n[[0]] | \n$=$ | \n0 | \n
$\\Longrightarrow$ | \n$x$ | \n$=$ | \n[[1]] | \n
Note: In the first gap, enter the quadratic in factored form.
\nNote: In the second gap, if $x=1,2$, enter set(1,2).
\n\n", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "gaps": [{"notallowed": {"message": "Ensure you factorise the expression.
", "showStrings": false, "strings": ["xx", "x^2", "x**2"], "partialCredit": 0}, "vsetrangepoints": 5, "expectedvariablenames": ["x"], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "answersimplification": "all", "scripts": {}, "answer": "(x+{a})(x+{b})", "marks": 1, "checkvariablenames": true, "checkingtype": "absdiff", "type": "jme", "musthave": {"message": "Ensure you factorise the expression.
", "showStrings": false, "strings": ["(", ")"], "partialCredit": 0}}, {"vsetrangepoints": 5, "expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "scripts": {}, "answer": "{monicsoln}", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme"}], "steps": [{"prompt": "Since $(x+a)(x+b)=x^2+(a+b)x+ab$, when we are factorising a quadratic, such as $x^2+cx+d$, we must find the numbers $a$ and $b$ such that $c=a+b$ and $d=ab$.
\n\nIn the case of $\\simplify{x^2+{linear}x+{const}}$ we ask
\nwhat two numbers add to give $\\var{linear}$ and multiply to give $\\var{const}$?
\nTherefore the numbers must be $\\var{a}$ and $\\var{b}$, that is
\n$\\simplify{x^2+{linear}x+{const}}=(\\simplify{x+{a}})(\\simplify{x+{b}}).$
\nYou can check this by expanding the binomial product.
", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "information"}, {"prompt": "Now, using the null factor law we have, either $\\simplify{x+{a}}=0$ or $\\simplify{x+{b}}=0$. In otherwords, either $x=\\var{-a}$ or $\\var{-b}$.
\n\n\n | $\\simplify{x^2+{linear}x+{const}}$ | \n$=$ | \n0 | \n
$\\Longrightarrow$ | \n$ (\\simplify{x+{a}})(\\simplify{x+{b}})$ | \n$=$ | \n0 | \n
$\\Longrightarrow$ | \n$x$ | \n$=$ | \n$\\var{-a},\\var{-b}$ | \n