// Numbas version: finer_feedback_settings
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a)
\nWe start solving the equation one operation at a time by doing the inverse to both sides, when we get to undoing the exponential we apply a log to both sides, we then use a log law and continue solving.
\n\n\n\n\n$\\var{a}$ | \n$=$ | \n$\\simplify{{p}({b})^(n/{d})+{c}}$ | \n | \n
\n\n$\\simplify{{a-c}}$ | \n$=$ | \n$\\simplify{{p}({b})^(n/{d})}$ | \n(subtract $\\var{c}$ from both sides) | \n
\n\n$\\var{frac}$ | \n$=$ | \n$\\simplify{{b}^(n/{d})}$ | \n(divide both sides by $\\var{p}$) | \n
\n\n$\\log(\\var{frac})$ | \n$=$ | \n$\\log(\\var{b}^{\\frac{n}{\\var{d}}})$ | \n(take the log of both sides) | \n
\n\n | \n$=$ | \n$\\frac{n}{\\var{d}}\\log(\\var{b})$ | \n(use a log law) | \n
\n\n | \n | \n | \n | \n
\n\n$\\displaystyle{\\frac{\\log(\\var{frac})}{\\log(\\var{b})}}$ | \n$=$ | \n$\\frac{n}{\\var{d}}$ | \n(divide both sides by $\\log(\\var{b})$) | \n
\n\n | \n | \n | \n | \n
\n\n$\\displaystyle{\\frac{\\var{d}\\log(\\var{frac})}{\\log(\\var{b})}}$ | \n$=$ | \n$n$ | \n(multiply both sides by $\\var{d}$) | \n
\n\n
\n\nb)
\nWe start solving the equation one operation at a time by doing the inverse to both sides, when we get to undoing the exponential we apply a log to both sides, we then use a log law and continue solving.
\n\n\n\n\n${\\var{FV}}$ | \n$=$ | \n$\\displaystyle{\\simplify{{pay}((1+{int})^n-1)/{int}}}$ | \n | \n
\n\n$\\simplify{{FV*int}}$ | \n$=$ | \n$\\displaystyle{\\simplify{{pay}((1+{int})^n-1)}}$ | \n(multiply both sides by $\\var{int}$) | \n
\n\n$\\displaystyle{\\simplify[simplifyFractions]{{FV*int}/{pay}}}$ | \n$=$ | \n$\\displaystyle{\\simplify{(1+{int})^n-1}}$ | \n(divide both sides by $\\var{pay}$) | \n
\n\n$\\displaystyle{\\simplify[simplifyFractions]{{FV*int}/{pay}+1}}$ | \n$=$ | \n$\\displaystyle{\\simplify{(1+{int})^n}}$ | \n(add $1$ to both sides) | \n
\n\n$\\displaystyle{\\simplify[simplifyFractions]{{FV*int+pay}/{pay}}}$ | \n$=$ | \n$\\displaystyle{\\simplify{(1+{int})^n}}$ | \n(tidy up left hand side) | \n
\n\n | \n | \n | \n | \n
\n\n$\\displaystyle{\\log\\left(\\simplify[simplifyFractions]{{FV*int+pay}/{pay}}\\right)}$ | \n$=$ | \n$\\displaystyle{\\log\\left((\\var{1+int})^n\\right)}$ | \n(take the log of both sides) | \n
\n\n | \n | \n | \n | \n
\n\n$\\displaystyle{\\log\\left(\\simplify[simplifyFractions]{{FV*int+pay}/{pay}}\\right)}$ | \n$=$ | \n$\\displaystyle{n\\log(\\var{1+int})}$ | \n(use a log law) | \n
\n\n | \n | \n | \n | \n
\n\n$\\displaystyle{\\frac{\\log\\left(\\simplify[simplifyFractions]{{FV*int+pay}/{pay}}\\right)}{\\log(\\var{1+int})}}$ | \n$=$ | \n$n$ | \n(divide both sides by $\\log(\\var{1+int})$) | \n
\n\n
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\n$\\begin{align*}\\simplify{{a}={p}({b})^(n/{d})+{c}}.\\end{align*}$
\n\n$n=$ [[0]]
\n
\nNote: Typing $\\log(5)$ will input the value $\\log_{10}(5)$, whereas $\\log5$ will not work.
Note: Typing $\\ln(5)$ will input the value $\\log_e(5)$, whereas $\\ln5$ will not work.
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\n$\\displaystyle{\\simplify{{FV}={pay}((1+{int})^n-1)/{int}}}.$
\n\n$n=$ [[0]]
\n
\nNote: Typing $\\log(5)$ will input the value $\\log_{10}(5)$, whereas $\\log5$ will not work.
Note: Typing $\\ln(5)$ will input the value $\\log_e(5)$, whereas $\\ln5$ will not work.
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