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Complete the following conversion from imperial to metric units (preferably without the use of a calculator).

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A patient reports their weight to be $\\var{massst} \\text{ st (stones) and } \\var{masslb} \\text{ lb (pounds)}$. Find their weight in kilograms correct to one decimal place by using that $1 \\text{ st} = 14 \\text{ lb}$ and $1 \\text{ lb} = 0.4536 \\text{ kg}$.

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Weight $=$ [[0]] kg (1 dec. pl.)

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$1 \\text{ st} = 14 \\text{lb}$, and so $\\var{massst} \\text{ st}= \\var{massst} \\times 14 \\text{ lbs} = \\var{st2lb} \\text{ lbs}$.

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Add on the additional $\\var{masslb} \\text{ lbs}$, and the patient's weight in pounds is $\\var{totlbs} \\text{ lbs}$.

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Given $1 \\text{ lb} = 0.4536 \\text{ kg}$, we must have $\\var{totlbs} \\text{ lbs} = \\var{totlbs} \\times 0.4536 \\text{ kg}$.

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We could use the calculator for this but we should also be able to do it without one.

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Without a calculator we determine $\\var{totlbs}\\times 4536$ (which is $\\var{precround(masskg*10000,0)}$) and then move the decimal place so we have four decimal places again (that is $\\var{masskg}$). Once we have done the multiplication we can then round to one decimal place (that is, $\\var{onedec}$ $\\var{onedec}.0$).

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$\\text{Weight} = \\var{masskg}\\text{ kg} = \\var{onedec}.0 \\text{ kg (1 dec. pl)}$

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$\\text{Weight} = \\var{masskg}\\text{ kg} = \\var{onedec} \\text{ kg (1 dec. pl)}$

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