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Given f(x)=1/(a-x)^2, evaluate f(x/z) where a is a randomised constant, and z is a randomised letter.

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Given $\\displaystyle{f(x)=\\frac{1}{(\\var{a}-x)^2}}$, evaluate $\\displaystyle{ f\\left( \\frac{x}{\\var{ve}}\\right) }$

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\\[\\begin{align*} f\\left( \\frac{x}{\\var{ve}}\\right)&= \\var{ans}\\\\ &= \\frac{1}{\\var{a}^2-2\\times\\var{a}\\frac{x}{\\var{ve}}+\\frac{x^2}{\\var{ve}^2} }\\\\&=\\frac{1}{\\frac{\\var{ve}^2\\var{a}^2-\\var{2*a}\\var{ve}x+x^2}{\\var{ve}^2}}\\\\&=\\frac{\\var{ve}^2}{\\var{a^2}\\var{ve}^2-\\var{2*a}\\var{ve}x+x^2}\\end{align*}\\]

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