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Using given information to complete the equation $c= A \\cos{ \\left( \\frac{2 \\pi}{P} \\left( t-H \\right) \\right) }+V $ that describes the concentration, $c$, of perscribed drug in a patient's drug over time, $t$. Calculating the maximum concentration and the concentration at a specific time. 

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A patient takes a drug every $\\var{P}$ hours each day. The concentration, $c$, of the drug in the patient’s blood $t$ hours after the start of the treatment is modelled by the equation:
$c=\\var{A}\\cos{\\left(k\\left(t-\\var{H}\\right)\\right)}+\\var{V}$

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a) The equation

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\\[ \\begin{split} c=\\var{A}\\cos{\\left(k\\left(t-\\var{H}\\right)\\right)}+\\var{V} \\end{split} \\]

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is a wave function.

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The general form of a wave function can be written as:

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\\[ \\begin{split} c=A\\cos{\\left(\\frac{2 \\pi}{P}\\left(t-H\\right)\\right)}+V \\end{split} \\]

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Where $V$ is the average value, $A$ is the amplitute, $H$ the phase and $P$ the period. 

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By comparying the equation with the general form we can notice that 

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\\[ k= \\frac{2 \\pi}{P} \\]

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We know that the patient takes the drug every $\\var{P}$ hours each day. Therefore, the period is $P=\\var{P}$. Therefore, 

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\\[ \\begin{split} k&= \\frac{2 \\pi}{\\var{P}} \\\\ &=\\simplify{  {2*pi} / {P}} \\end{split} \\]

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So, $k=\\simplify{  {2*pi} / {P}}$ and we can now rewrite the equation as:

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\\[ \\begin{split} c=\\var{A}\\cos{\\left(\\simplify{  {2*pi} / {P}}\\left(t-\\var{H}\\right)\\right)}+\\var{V} \\end{split} \\]

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b) We know that the wave function is a transformation of the trigonometric function cos(x). 

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Clink on the link for a visual representation of the wave function.

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https://www.desmos.com/calculator/ssqdx7ys7k

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We also know that the cosine function has a maximum value of 1. So, the maximum value of the wave function will occure when $ \\cos{\\left(\\simplify{  {2*pi} / {P}}\\left(t-\\var{H}\\right)\\right)}=1$. Therefore, 

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\\[ \\begin{split} c_{max}&=\\var{A}\\times 1 +\\var{V} \\\\ &= \\var{A} +\\var{V} \\\\ &=\\var{A+V} \\end{split} \\]

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So, $c_{max}=\\var{max}$ mg/L.

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c) To calculate the concentration of the drug $\\var{t1}$ hours after taking it for the first time, we need to subtitute $t=\\var{t1}$ in the equation

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\\[ \\begin{split} c=\\var{A}\\cos{\\left(\\simplify{  {2*pi} / {P}}\\left(t-\\var{H}\\right)\\right)}+\\var{V} \\end{split} \\]

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Therefore, when $t=\\var{t1}$ the equation become

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\\[ \\begin{split} c_{\\var{t1}}&=\\var{A}\\cos{\\left(\\simplify{  {2*pi} / {P}}\\left(\\var{t1}-\\var{H}\\right)\\right)}+\\var{V} \\\\ &=\\var{A}\\cos{\\left(\\simplify{  {2*pi} / {P}} \\times \\var{t1-H}\\right)}+\\var{V} \\\\ &=\\var{A}\\cos{\\left(\\simplify{  {2*pi*(t1-H)}/{P}}\\right)}+\\var{V} \\\\ &=\\var{ansC}  \\end{split} \\]

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So, $ c_{\\var{t1}}=\\var{ansc} $ mg/L.

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Calculate the value of the constant $k$.

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$k=$[[0]]

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Give your answer as a fraction in terms of $\\pi$ (you can type: pi).

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What is the maximum concentration of the drug in the patient’s bloodstream at any time?

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$c_{max}=$[[0]] mg/L

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What is the concentration of the drug $\\var{t1}$ hours after taking it for the first time?

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$c_{\\var{t1}}=$[[0]]

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Give your answer rounded to 2 decimal places, if needed.

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