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For CGF $\\log(m(s))$ what is the formula to find the $k^{\\mbox{th}}$ cumulant?

", "advice": "

This can easily be taken from the coefficients of $\\frac{s^k}{k!}$ without needing to derive.

\n

These are useful for finding the below:
$\\begin{align*}
k_1 &= \\mu = E[X] \\\\
k_2 &= \\mu_2 = Var[X] \\\\
k_3 &= \\mu_3 = (3rd\\text{ central moment}) \\\\
k_4 &= \\mu_4 - 3 \\sigma^4 = (4th\\text{ central moment} - 3 \\sigma^4)
\\end{align*}$

\n

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