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Let $X$ and $Y$ be two continuous random variables with joint pdf $f(x, y)$.

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With $U=u(X,Y)$ and $V=v(X,Y)$ that are both 1-1 functions

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How can we find the conditional distributions $g(u|v)$ using no other information?

", "advice": "

To find the conditional distribution through a transformation we must find the joint and marginal to use in Bayes rule.

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    \n
  1. First find the joint pdf $g(u,v)$ using a bivariate transformation
  2. \n
  3. Find the marginal $g(v) = \\int_Ug(u,v) du$
  4. \n
  5. Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(v)}$
  6. \n
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    \n
  1. First find the joint pdf $g(u,v)$ using a bivariate transformation
  2. \n
  3. Find the marginal $g(v) = \\int_Ug(u,v) du$
  4. \n
  5. Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(v)}$
  6. \n
", "
    \n
  1. First find the joint pdf $g(u,v)$ using a bivariate transformation
  2. \n
  3. Find the marginal $g(u) = \\int_Vg(u,v) dv$
  4. \n
  5. Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(u)}$
  6. \n
", "
    \n
  1. Find the conditional $f(x|y)$
  2. \n
  3. Transform $f(x|y) \\to g(u|v)$
  4. \n
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