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Let $X$ and $Y$ be two continuous random variables with joint pdf $f(x, y)$.
\nWith $U=u(X,Y)$ and $V=v(X,Y)$ that are both 1-1 functions
\nHow can we find the conditional distributions $g(u|v)$ using no other information?
", "advice": "To find the conditional distribution through a transformation we must find the joint and marginal to use in Bayes rule.
\n\n- First find the joint pdf $g(u,v)$ using a bivariate transformation
\n- Find the marginal $g(v) = \\int_Ug(u,v) du$
\n- Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(v)}$
\n
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\n- Find the marginal $g(v) = \\int_Ug(u,v) du$
\n- Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(v)}$
\n
", "\n- First find the joint pdf $g(u,v)$ using a bivariate transformation
\n- Find the marginal $g(u) = \\int_Vg(u,v) dv$
\n- Use Bayes rule to find the conditional $g(u|v) = \\frac{g(u,v)}{g(u)}$
\n
", "\n- Find the conditional $f(x|y)$
\n- Transform $f(x|y) \\to g(u|v)$
\n
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